為什么我的python代碼無法正常運行？

Question

我的python代碼如下，但無法正常工作。

import random

secret = random.randint (1, 99)
guess = 0
tries = 0

print "AHOY! I'm the Dread Pirate Oliver and I have a secret!"
print "I will tell you where my treasure is buried if you can guess the number that I'm thinking of."
print "It is a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE FIRST WORD IS: Awesome"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()

import random

secret = random.randint (1, 99)
guess = 0
tries = 0

print "AHOY THERE!"
print "ME AGAIN"
print "I will tell you the second word if you can guess the number that I'm thinking of."
print "It is a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE SECOND WORD IS: Land"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()    

import random

secret = random.randint (1, 3)
guess = 0
tries = 0

print "AHOY! One more thing"
print "It is a number from 1 to 3. I'll give you 1 try."

while guess != secret and tries < 1:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "It's buried in the sand at 36 degrees North, 48 degrees east."
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()
import random

secret = random.randint (1, 99)
guess = 0
tries = 0
print "Congratz. You won!"

在抬高SystemExit（）部分中，我希望該人如果沒有猜到最后一點就無法繼續。 它甚至還沒有開始，但是當我拿出抬高的SystemExit（）時，它可以工作，但即使他們猜對了，它仍然可以繼續。 我該怎么做才能做我想做的？

Answer 1

該行應縮進，使其成為else塊的一部分，否則即使猜測正確也將始終執行該行：

raise SystemExit()

最好也改為調用sys.exit() 。

同樣，如果您想做兩次，而不是復制和粘貼代碼，則應創建一個函數並調用兩次：

def play():
    # ...

number_of_games = 2
for i in range(number_of_games):
    play()

Answer 2

要退出Python中的腳本，您只想使用sys.exit ：

import sys
code = 0
sys.exit(code)

代碼是腳本的返回代碼。 如果腳本沒有錯誤，則應該為零，否則為1到127之間的任何數字。 用戶錯誤不是腳本錯誤，因此，如果您的用戶不猜，則只需輸入0。

Answer 3

您應該嘗試創建一個函數，而不要過多地復制粘貼，這可能會解決部分問題。 我認為其中一些代碼已經過時了...

我們想把它放在下面的while循環中：

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE FIRST WORD IS: Awesome"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()

在它上面的while循環中：

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

因此，使用此代碼創建一個名為guess_check（）的函數

例如：

secret = 3
tries = 0
guess = 0

def guess_check():
    if int(guess) < secret:
        print ("Too low, ye scurvy dog!")
    elif int(guess) > secret:
        print ("Too high, landlubber!")
    elif int(guess) == secret:
        print ("Avast! Ye got it! Found ma secret number, ye did!")
        print ("THE FIRST WORD IS: Awesome")
    elif tries == 6:
        print ("No more guesses! Better luck next time, Matey!")
        print ("Ma secret number wuz", secret)


while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    tries = tries + 1
    guess_check();
    if guess == secret:
        break
    elif tries == 6:
        break
    else:
        pass

這段代碼只是一個起點，您需要對其進行調整以滿足您的需求，我不是在為您做業余愛好:)，但希望對您有所幫助！