为什么我的python代码无法正常运行？

Question

我的python代码如下，但无法正常工作。

import random

secret = random.randint (1, 99)
guess = 0
tries = 0

print "AHOY! I'm the Dread Pirate Oliver and I have a secret!"
print "I will tell you where my treasure is buried if you can guess the number that I'm thinking of."
print "It is a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE FIRST WORD IS: Awesome"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()

import random

secret = random.randint (1, 99)
guess = 0
tries = 0

print "AHOY THERE!"
print "ME AGAIN"
print "I will tell you the second word if you can guess the number that I'm thinking of."
print "It is a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE SECOND WORD IS: Land"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()    

import random

secret = random.randint (1, 3)
guess = 0
tries = 0

print "AHOY! One more thing"
print "It is a number from 1 to 3. I'll give you 1 try."

while guess != secret and tries < 1:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "It's buried in the sand at 36 degrees North, 48 degrees east."
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()
import random

secret = random.randint (1, 99)
guess = 0
tries = 0
print "Congratz. You won!"

在抬高SystemExit（）部分中，我希望该人如果没有猜到最后一点就无法继续。 它甚至还没有开始，但是当我拿出抬高的SystemExit（）时，它可以工作，但即使他们猜对了，它仍然可以继续。 我该怎么做才能做我想做的？

Answer 1

该行应缩进，使其成为else块的一部分，否则即使猜测正确也将始终执行该行：

raise SystemExit()

最好也改为调用sys.exit() 。

同样，如果您想做两次，而不是复制和粘贴代码，则应创建一个函数并调用两次：

def play():
    # ...

number_of_games = 2
for i in range(number_of_games):
    play()

Answer 2

要退出Python中的脚本，您只想使用sys.exit ：

import sys
code = 0
sys.exit(code)

代码是脚本的返回代码。 如果脚本没有错误，则应该为零，否则为1到127之间的任何数字。 用户错误不是脚本错误，因此，如果您的用户不猜，则只需输入0。

Answer 3

您应该尝试创建一个函数，而不要过多地复制粘贴，这可能会解决部分问题。 我认为其中一些代码已经过时了...

我们想把它放在下面的while循环中：

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE FIRST WORD IS: Awesome"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()

在它上面的while循环中：

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

因此，使用此代码创建一个名为guess_check（）的函数

例如：

secret = 3
tries = 0
guess = 0

def guess_check():
    if int(guess) < secret:
        print ("Too low, ye scurvy dog!")
    elif int(guess) > secret:
        print ("Too high, landlubber!")
    elif int(guess) == secret:
        print ("Avast! Ye got it! Found ma secret number, ye did!")
        print ("THE FIRST WORD IS: Awesome")
    elif tries == 6:
        print ("No more guesses! Better luck next time, Matey!")
        print ("Ma secret number wuz", secret)


while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    tries = tries + 1
    guess_check();
    if guess == secret:
        break
    elif tries == 6:
        break
    else:
        pass

这段代码只是一个起点，您需要对其进行调整以满足您的需求，我不是在为您做业余爱好:)，但希望对您有所帮助！