[英]Help calculating average per day
daily_average
列始終返回零。 默認時間戳記值是過去一周的值。 在我做錯了在這里得到每天的平均訂單價值是什么有什么想法?
SELECT
SUM(price+shipping_price) AS total_sales,
COUNT(id) AS total_orders,
AVG(price+shipping_price) AS order_total_average,
(SELECT
SUM(quantity)
FROM `order_product`
INNER JOIN `order` ON (
`order`.id = order_product.order_id AND
`order`.created >= '.$startTimestamp.' AND
`order`.created <= '.$endTimestamp.' AND
`order`.type_id = '.$type->getId().' AND
`order`.fraud = 0
)
) as total_units,
SUM(price+shipping_price)/DATEDIFF('.$endTimestamp.', '.$startTimestamp.') as daily_average
FROM `order`
WHERE created >= '.$startTimestamp.' AND
created <= '.$endTimestamp.' AND
fraud = 0 AND
type_id = '.$type->getId().'
您正在使用聚合函數( SUM , COUNT , AVG )而沒有聚合命令(分組依據)。 我認為您的SQL比需要的要復雜(不需要內部選擇)。
這是一條應該起作用的SQL命令(沒有測試數據就很難進行測試;)
SELECT
COUNT(id) total_orders,
SUM(finalprice) total_sales,
AVG(finalprice) order_average,
SUM(units) total_units,
SUM(finalprice)/DATEDIFF('.$endTimestamp.', '.$startTimestamp.') daily_average
FROM (
SELECT
o.id id,
o.price+o.shipping_price finalprice,
SUM(p.quantity) units
FROM order o INNER JOIN order_product p ON p.order_id=o.id
WHERE o.created>='.$startTimestamp.'
AND o.created<='.$endTimestamp.'
AND o.fraud=0
AND o.type_id='.$type->getId().'
GROUP BY p.order_id
) t;
轉換部門中的元素之一對您有用嗎?
SELECT
SUM(price+shipping_price) AS total_sales,
COUNT(id) AS total_orders,
AVG(price+shipping_price) AS order_total_average,
(SELECT
SUM(quantity)
FROM `order_product`
INNER JOIN `order` ON (
`order`.id = order_product.order_id AND
`order`.created >= '.$startTimestamp.' AND
`order`.created <= '.$endTimestamp.' AND
`order`.type_id = '.$type->getId().' AND
`order`.fraud = 0
)
) as total_units,
CAST(SUM(price+shipping_price) AS float)/DATEDIFF('.$endTimestamp.', '.$startTimestamp.') as daily_average
FROM `order`
WHERE created >= '.$startTimestamp.' AND
created <= '.$endTimestamp.' AND
fraud = 0 AND
type_id = '.$type->getId().'
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