正則表達式在公式中查找分隔符點

Question

我使用的C＃表達式庫不會直接支持我的表/字段參數語法：

以下是不直接支持的表/字段參數名稱：

TableName1.FieldName1
[TableName1].[FieldName1]
[Table Name 1].[Field Name 1]

它接受不帶空格的字母數字參數，或大括號括在方括號內的大多數字符。 我想使用C＃正則表達式將點分隔符和相鄰括號替換為不同的分隔符，因此結果如下：

[TableName1|FieldName1]
[TableName1|FieldName1]
[Table Name 1|Field Name 1]

我還需要在單引號內跳過任何字符串文字，例如：

'TableName1.FieldName1'

當然，忽略任何數字文字，如：

12345.6789

編輯：感謝您就改進我的問題提出的反饋意見。 希望現在更清楚了。

Answer 1

我已經寫了一個全新的答案，現在澄清了問題：

您可以在單個正則表達式中執行此操作。 我認為它非常防彈，但正如你所看到的，它並不是完全不言自明的，這就是為什么我自由地評論它。 希望它有意義。

你很幸運.NET允許重用命名的捕獲組，否則你必須分幾步完成。

resultString = Regex.Replace(subjectString, 
    @"(?:             # Either match...
     (?<before>       #  (and capture into backref <before>)
      (?=\w*\p{L})    #  (as long as it contains at least one letter):
      \w+             #  one or more alphanumeric characters,
     )                #  (End of capturing group <before>).
     \.               #  then a literal dot,
     (?<after>        #  (now capture again, into backref <after>)
      (?=\w*\p{L})    #  (as long as it contains at least one letter):
      \w+             #  one or more alphanumeric characters.
     )                #  (End of capturing group <after>) and end of match.
    |                 # Or:
     \[               #  Match a literal [
     (?<before>       #  (now capture into backref <before>)
      [^\]]+          #  one or more characters except ]
     )                #  (End of capturing group <before>).
     \]\.\[           #  Match literal ].[
     (?<after>        #  (capture into backref <after>)
      [^\]]+          #  one or more characters except ]
     )                #  (End of capturing group <after>).
     \]               #  Match a literal ]
    )                 # End of alternation. The match is now finished, but
    (?=               # only if the rest of the line matches either...
     [^']*$           #  only non-quote characters
     |                # or
     [^']*'[^']*'     #  contains an even number of quote characters
     [^']*            #  plus any number of non-quote characters
     $                #  until the end of the line.
    )                 # End of the lookahead assertion.", 
    "[${before}|${after}]", RegexOptions.Multiline | RegexOptions.IgnorePatternWhitespace);

Answer 2

希望你可以試試這個正則表達式： /(\\w[0-9]* *)+/g這會過濾掉除了之外的所有字母數字。