Linq表達式和擴展方法獲取屬性名稱

Question

我正在看這篇文章，它描述了在POCO屬性之間進行數據綁定的簡單方法： 數據綁定POCO屬性

Bevan的評論之一包括一個簡單的Binder類，可用於完成此類數據綁定。 它對我需要的東西很有用，但我想實現Bevan為改進課程所做的一些建議，即：

• 檢查是否已分配源和目標
• 檢查sourcePropertyName和targetPropertyName標識的屬性是否存在
• 檢查兩個屬性之間的類型兼容性

此外，鑒於按字符串指定屬性容易出錯，您可以使用Linq表達式和擴展方法。 然后而不是寫作

Binder.Bind( source, "Name", target, "Name")

你可以寫

source.Bind( Name => target.Name);

我很確定我可以處理前三個（盡管可以隨意包含這些更改）但我不知道如何使用Linq表達式和擴展方法來編寫代碼而不使用屬性名稱字符串。

有小費嗎？

以下是鏈接中的原始代碼：

public static class Binder
{

    public static void Bind(
        INotifyPropertyChanged source,
        string sourcePropertyName,
        INotifyPropertyChanged target,
        string targetPropertyName)
    {
        var sourceProperty
            = source.GetType().GetProperty(sourcePropertyName);
        var targetProperty
            = target.GetType().GetProperty(targetPropertyName);

        source.PropertyChanged +=
            (s, a) =>
            {
                var sourceValue = sourceProperty.GetValue(source, null);
                var targetValue = targetProperty.GetValue(target, null);
                if (!Object.Equals(sourceValue, targetValue))
                {
                    targetProperty.SetValue(target, sourceValue, null);
                }
            };

        target.PropertyChanged +=
            (s, a) =>
            {
                var sourceValue = sourceProperty.GetValue(source, null);
                var targetValue = targetProperty.GetValue(target, null);
                if (!Object.Equals(sourceValue, targetValue))
                {
                    sourceProperty.SetValue(source, targetValue, null);
                }
            };
    }
}

Answer 1

以下將從lambda表達式返回屬性名稱作為字符串：

public string PropertyName<TProperty>(Expression<Func<TProperty>> property)
{
  var lambda = (LambdaExpression)property;

  MemberExpression memberExpression;
  if (lambda.Body is UnaryExpression)
  {
    var unaryExpression = (UnaryExpression)lambda.Body;
    memberExpression = (MemberExpression)unaryExpression.Operand;
  }
  else
  {
    memberExpression = (MemberExpression)lambda.Body;
  }

  return memberExpression.Member.Name;
}

用法：

public class MyClass
{
  public int World { get; set; }
}

...
var c = new MyClass();
Console.WriteLine("Hello {0}", PropertyName(() => c.World));

UPDATE

public static class Extensions
{
    public static void Bind<TSourceProperty, TDestinationProperty>(this INotifyPropertyChanged source, Expression<Func<TSourceProperty, TDestinationProperty>> bindExpression)
    {
        var expressionDetails = GetExpressionDetails<TSourceProperty, TDestinationProperty>(bindExpression);
        var sourcePropertyName = expressionDetails.Item1;
        var destinationObject = expressionDetails.Item2;
        var destinationPropertyName = expressionDetails.Item3;

        // Do binding here
        Console.WriteLine("{0} {1}", sourcePropertyName, destinationPropertyName);
    }

    private static Tuple<string, INotifyPropertyChanged, string> GetExpressionDetails<TSourceProperty, TDestinationProperty>(Expression<Func<TSourceProperty, TDestinationProperty>> bindExpression)
    {
        var lambda = (LambdaExpression)bindExpression;

        ParameterExpression sourceExpression = lambda.Parameters.FirstOrDefault();
        MemberExpression destinationExpression = (MemberExpression)lambda.Body;

        var memberExpression = destinationExpression.Expression as MemberExpression;
        var constantExpression = memberExpression.Expression as ConstantExpression;
        var fieldInfo = memberExpression.Member as FieldInfo;
        var destinationObject = fieldInfo.GetValue(constantExpression.Value) as INotifyPropertyChanged;

        return new Tuple<string, INotifyPropertyChanged, string>(sourceExpression.Name, destinationObject, destinationExpression.Member.Name);
    }
}

用法：

public class TestSource : INotifyPropertyChanged
{
    public event PropertyChangedEventHandler PropertyChanged;

    public string Name { get; set; }        
}

public class TestDestination : INotifyPropertyChanged
{
    public event PropertyChangedEventHandler PropertyChanged;

    public string Id { get; set; }    
}

class Program
{        
    static void Main(string[] args)
    {
        var x = new TestSource();
        var y = new TestDestination();

        x.Bind<string, string>(Name => y.Id);
    }    
}

Answer 2

這個問題非常類似於： 從lambda表達式中檢索屬性名稱

（來自https://stackoverflow.com/a/17220748/1037948的交叉發布回復）

我不知道你是否需要綁定到“ lambda.Body ”，但是檢查lambda.Body for Member.Name只會返回“final”屬性，而不是“完全限定”屬性。

ex） o => o.Thing1.Thing2會導致Thing2 ，而不是Thing1.Thing2 。

當嘗試使用此方法來簡化具有表達式重載的EntityFramework DbSet.Include(string)時，這會出現問題。

所以你可以“欺騙”並解析Expression.ToString 。 在我的測試中，性能似乎相當，所以如果這是一個壞主意，請糾正我。

擴展方法

/// <summary>
/// Given an expression, extract the listed property name; similar to reflection but with familiar LINQ+lambdas.  Technique @via https://stackoverflow.com/a/16647343/1037948
/// </summary>
/// <remarks>Cheats and uses the tostring output -- Should consult performance differences</remarks>
/// <typeparam name="TModel">the model type to extract property names</typeparam>
/// <typeparam name="TValue">the value type of the expected property</typeparam>
/// <param name="propertySelector">expression that just selects a model property to be turned into a string</param>
/// <param name="delimiter">Expression toString delimiter to split from lambda param</param>
/// <param name="endTrim">Sometimes the Expression toString contains a method call, something like "Convert(x)", so we need to strip the closing part from the end</pa ram >
/// <returns>indicated property name</returns>
public static string GetPropertyName<TModel, TValue>(this Expression<Func<TModel, TValue>> propertySelector, char delimiter = '.', char endTrim = ')') {

    var asString = propertySelector.ToString(); // gives you: "o => o.Whatever"
    var firstDelim = asString.IndexOf(delimiter); // make sure there is a beginning property indicator; the "." in "o.Whatever" -- this may not be necessary?

    return firstDelim < 0
        ? asString
        : asString.Substring(firstDelim+1).TrimEnd(endTrim);
}//--   fn  GetPropertyNameExtended

（檢查分隔符可能甚至是過度殺傷）

Answer 3

var pr = typeof（CCategory）.GetProperties（）。選擇（i => i.Name）.ToList（）; ;

Answer 4

宣言：

    class Foo<T> {
            public string Bar<T, TResult>(Expression<Func<T, TResult>> expersion)
            {
                var lambda = (LambdaExpression)expersion;
                MemberExpression memberExpression;
                if (lambda.Body is UnaryExpression)
                {
                    var unaryExpression = (UnaryExpression)lambda.Body;
                    memberExpression = (MemberExpression)unaryExpression.Operand;
                }
                else
                {
                    memberExpression = (MemberExpression)lambda.Body;
                }

                return memberExpression.Member.Name;
            }
    }

用法：

    var foo = new Foo<DummyType>();
    var propName = foo.Bar(d=>d.DummyProperty)
    Console.WriteLine(propName); //write "DummyProperty" string in shell

Answer 5

這可能不僅僅是你要求的，但我已經做了類似的事情來處理兩個對象之間的屬性映射：

public interface IModelViewPropagationItem<M, V>
    where M : BaseModel
    where V : IView
{
    void SyncToView(M model, V view);
    void SyncToModel(M model, V view);
}

public class ModelViewPropagationItem<M, V, T> : IModelViewPropagationItem<M, V>
    where M : BaseModel
    where V : IView
{
    private delegate void VoidDelegate();

    public Func<M, T> ModelValueGetter { get; private set; }
    public Action<M, T> ModelValueSetter { get; private set; }
    public Func<V, T> ViewValueGetter { get; private set; }
    public Action<V, T> ViewValueSetter { get; private set; }

    public ModelViewPropagationItem(Func<M, T> modelValueGetter, Action<V, T> viewValueSetter)
        : this(modelValueGetter, null, null, viewValueSetter)
    { }

    public ModelViewPropagationItem(Action<M, T> modelValueSetter, Func<V, T> viewValueGetter)
        : this(null, modelValueSetter, viewValueGetter, null)
    { }

    public ModelViewPropagationItem(Func<M, T> modelValueGetter, Action<M, T> modelValueSetter, Func<V, T> viewValueGetter, Action<V, T> viewValueSetter)
    {
        this.ModelValueGetter = modelValueGetter;
        this.ModelValueSetter = modelValueSetter;
        this.ViewValueGetter = viewValueGetter;
        this.ViewValueSetter = viewValueSetter;
    }

    public void SyncToView(M model, V view)
    {
        if (this.ViewValueSetter == null || this.ModelValueGetter == null)
            throw new InvalidOperationException("Syncing to View is not supported for this instance.");

        this.ViewValueSetter(view, this.ModelValueGetter(model));
    }

    public void SyncToModel(M model, V view)
    {
        if (this.ModelValueSetter == null || this.ViewValueGetter == null)
            throw new InvalidOperationException("Syncing to Model is not supported for this instance.");

        this.ModelValueSetter(model, this.ViewValueGetter(view));
    }
}

這允許您創建此對象的實例，然后使用“SyncToModel”和“SyncToView”來回移動值。 下面的內容允許您對這些內容進行分組，並通過一次調用來回移動數據：

public class ModelViewPropagationGroup<M, V> : List<IModelViewPropagationItem<M, V>>
    where M : BaseModel
    where V : IView
{
    public ModelViewPropagationGroup(params IModelViewPropagationItem<M, V>[] items)
    {
        this.AddRange(items);
    }

    public void SyncAllToView(M model, V view)
    {
        this.ForEach(o => o.SyncToView(model, view));
    }

    public void SyncAllToModel(M model, V view)
    {
        this.ForEach(o => o.SyncToModel(model, view));
    }
}

用法看起來像這樣：

private static readonly ModelViewPropagationItem<LoginModel, ILoginView, string> UsernamePI = new ModelViewPropagationItem<LoginModel, ILoginView, string>(m => m.Username.Value, (m, x) => m.Username.Value = x, v => v.Username, (v, x) => v.Username = x);
private static readonly ModelViewPropagationItem<LoginModel, ILoginView, string> PasswordPI = new ModelViewPropagationItem<LoginModel, ILoginView, string>(m => m.Password.Value, (m, x) => m.Password.Value = x, v => v.Password, (v, x) => v.Password = x);
private static readonly ModelViewPropagationGroup<LoginModel, ILoginView> GeneralPG = new ModelViewPropagationGroup<LoginModel, ILoginView>(UsernamePI, PasswordPI);

public UserPrincipal Login_Click()
{
    GeneralPG.SyncAllToModel(this.Model, this.View);

    return this.Model.DoLogin();
}

希望這可以幫助！