ASP.net c＃LINQ for循環

Question

// Load all the links
ArtworkingDataContext dc = new ArtworkingDataContext();
var q = (from Labels in dc.tblArtworkLabels where Labels.templateID == this.ID select new { LabelID = Labels.ID });

// Create labels array
this.Labels = new ArtworkLabel[q.Count()];
for (int i = 0; i < q.Count(); i++)
{
    this.Labels[i] = new ArtworkLabel(q.LabelID);
}

q.LabelID不起作用，我不能真正使用foreach因為我必須在每次迭代時調用一個新的ArtworkLabel。

Answer 1

這可行：

var queryList = q.ToList();
for (int i = 0; i < queryList.Count; i++)
{
    this.Labels[i] = new ArtworkLabel(queryList[i].LabelID);
}

您也可以直接從查詢中進行投影：

this.Labels = dc.tblArtworkLabels
                .Where( x=> x.templateId == this.Id)
                .Select( x=> new ArtworkLabel(x.ID))
                .ToArray();

Answer 2

試試這樣：

this.Labels = q.Select(x => new ArtworkLabel(x.LabelID)).ToArray();

Answer 3

你可能會這樣做，對吧？

ArtworkingDataContext dc = new ArtworkingDataContext();

this.Labels = 
    from label in dc.tblArtworkLabels 
    where label.templateID == this.ID
    select new ArtworkLabel(label.ID).ToArray();

Answer 4

您應該能夠在一個linq語句中完成所有操作。

ArtworkingDataContext dc = new ArtworkingDataContext();
this.Labels = (from Labels in dc.tblArtworkLabels where Labels.templateID == this.ID select new ArtworkLabel(Labels.ID)).ToArray();

Answer 5

我最近嘗試了這個，一個linq for loop ..這就是我想出的......

        var query = from ii in Enumerable.Range(0, xml.AllIndexesOf("<item").Count())
                    where ii < xml.AllIndexesOf("<item").Count()
                    select new { Start = xml.AllIndexesOf("<item").ToList()[sii], Count = xml.AllIndexesOf("</item").ToList()[sii] - xml.AllIndexesOf("<item").ToList()[sii] };