使用動態變量解析JSON塊

Question

我從URL抓取JSON對象並使用JSON.NET解析它。 我能夠用定義的變量解析數據塊就好了，但是當涉及var：value的隨機收集時 - 我被卡住了。

示例（松散類型）：

{"FNAME":"joe","LNAME":"doe",
"BodyType":{"height":180,"weight":"200","race":"white","hair":"black"},
"BELONGINGS":{"shirt":"black","Money":15,"randomThing":"anyvar"},
"Signs":{"tattoo":0,"scar":"forehead","glasses":"dorky"}
}

我正在投這個

Class Person
{
public string FNAME;
public string LNAME;
public BodyType bodyType;
public ????? belongings;
public ????? signs;
}
如果我無法預測其屬性，我該如何處理物品和標志？

Answer 1

有兩種方法可以在不知道運行時的內容的情況下處理它們。

第一種方法是使用JSON.Net的JObject ，它將處理你提到的情況，以及層次結構。

第二種方法是使用System.Dynamic的ExpandoObject ，這是最新版本的JSON.Net新支持的。 不幸的是，它並沒有完全處理層次結構，但JSON.Net在遇到時會回到JObject支持它們。 出於您的目的，它可能更直接。

以下是您提供的代碼段和定義的示例。 另請注意， ExpandoObject可直接轉換為IDictionary<string, object> ，而JObject具有訪問屬性的顯式方法。

Person對應於ExpandoObject ，JPerson對應於JObject 。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

using System.Dynamic;

using Newtonsoft.Json;
using Newtonsoft.Json.Converters;
using Newtonsoft.Json.Linq;

namespace YourFavoriteNamespace
{
    public class JPerson
    {
        public string FNAME;
        public string LNAME;
        public BodyType bodyType;
        public JObject belongings;
        public JObject signs;
    }

    public class Person
    {
        public string FNAME;
        public string LNAME;
        public BodyType bodyType;
        public ExpandoObject belongings;
        public ExpandoObject signs;
    }

    public class BodyType
    {
        public int height;
        public int weight;
        public string race;
        public string hair;
    }

    class Program
    {
        static void DumpDynamic(dynamic d)
        {
            IDictionary<string, object> dynMap = (IDictionary<string, object>)d;
            foreach (string key in dynMap.Keys)
            {
                Console.WriteLine("  {0}={1} (type {2})", key, dynMap[key], null == dynMap[key] ? "null" : dynMap[key].GetType().Name);
            }
        }

        static void DumpJProperties(JObject jo)
        {
            var props = jo.Properties();
            foreach (JProperty prop in props)
            {
                Console.WriteLine("  {0}={1} (type {2})", prop.Name, prop.Value, null == prop.Value ? "null" : prop.Value.GetType().Name);
            }
        }

        static void DumpPerson(Person p)
        {
            Console.WriteLine("Person");
            Console.WriteLine("  FNAME={0}", p.FNAME);
            Console.WriteLine("  LNAME={0}", p.LNAME);
            Console.WriteLine("Person.BodyType");
            Console.WriteLine("  height={0}", p.bodyType.height);
            Console.WriteLine("  weight={0}", p.bodyType.weight);
            Console.WriteLine("  race  ={0}", p.bodyType.race);
            Console.WriteLine("  hair  ={0}", p.bodyType.hair);
            Console.WriteLine("Person.belongings");
            DumpDynamic(p.belongings);
            Console.WriteLine("Person.signs");
            DumpDynamic(p.signs);
        }

        static void DumpJPerson(JPerson p)
        {
            Console.WriteLine("Person");
            Console.WriteLine("  FNAME={0}", p.FNAME);
            Console.WriteLine("  LNAME={0}", p.LNAME);
            Console.WriteLine("Person.BodyType");
            Console.WriteLine("  height={0}", p.bodyType.height);
            Console.WriteLine("  weight={0}", p.bodyType.weight);
            Console.WriteLine("  race  ={0}", p.bodyType.race);
            Console.WriteLine("  hair  ={0}", p.bodyType.hair);
            Console.WriteLine("Person.belongings");
            DumpJProperties(p.belongings);
            Console.WriteLine("Person.signs");
            DumpJProperties(p.signs);
        }

        static void DoSimplePerson()
        {
            string initJson = "{\"FNAME\":\"joe\",\"LNAME\":\"doe\",\"BodyType\":{\"height\":180,\"weight\":\"200\",\"race\":\"white\",\"hair\":\"black\"},\"BELONGINGS\":{\"shirt\":\"black\",\"Money\":15,\"randomThing\":\"anyvar\"},\"Signs\":{\"tattoo\":0,\"scar\":\"forehead\",\"glasses\":\"dorky\"}}";
            Person p = JsonConvert.DeserializeObject<Person>(initJson);
            DumpPerson(p);
            Console.ReadLine();
        }

        static void DoComplexPerson()
        {
            string initJson = "{\"FNAME\":\"joe\",\"LNAME\":\"doe\",\"BodyType\":{\"height\":180,\"weight\":\"200\",\"race\":\"white\",\"hair\":\"black\"},\"BELONGINGS\":{\"shirt\":\"black\",\"Money\":15,\"randomThing\":\"anyvar\"},\"Signs\":{\"tattoo\":0,\"scar\":\"forehead\",\"glasses\":[\"dorky\",\"hipster\"]}}";
            Person p = JsonConvert.DeserializeObject<Person>(initJson);
            DumpPerson(p);
            Console.ReadLine();
        }

        static void DoJPerson()
        {
            string initJson = "{\"FNAME\":\"joe\",\"LNAME\":\"doe\",\"BodyType\":{\"height\":180,\"weight\":\"200\",\"race\":\"white\",\"hair\":\"black\"},\"BELONGINGS\":{\"shirt\":\"black\",\"Money\":15,\"randomThing\":\"anyvar\"},\"Signs\":{\"tattoo\":0,\"scar\":\"forehead\",\"glasses\":\"dorky\"}}";
            JPerson p = JsonConvert.DeserializeObject<JPerson>(initJson);
            DumpJPerson(p);
            Console.ReadLine();
        }

        static void Main(string[] args)
        {
            DoSimplePerson();
            DoComplexPerson();
            DoJPerson();
        }
    }
}

Answer 2

好吧，他們肯定是JSON對象，對，JSON對象是將字符串映射到某些東西的關聯數組。 所以我將它們表示為Dictionary<string, dynamic> - 一個字符串映射到某些東西。