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PHP准備語句 - 重置行指針

[英]PHP prepared statement - reset row pointer

我有下面的代碼,評論應該清楚地解釋。 我想查詢文件以獲取給定的信息,然后在返回結果后,在結果數組中添加一個字段。 然后,在我的程序中稍后訪問生成的數組。

以下代碼的問題是,我認為數組是第二次嘗試循環時的最后一條記錄...並且重置($ stmt1)失敗,因為$ stmt1“不是數組對象”...

<?php 

$sql1 = "SELECT dpdpt, SUM(dpbir) FROM dwhlib.dwdptstr WHERE dpdpt < '312' GROUP BY dpdpt ";

//Setup connection
$conn_resource = db2_connect ( "*LOCAL", "", "" );

//Verify connection successful
if (! $conn_resource) {
    echo "Connection failed. SQL Err:";
    echo db2_conn_error ();
    echo "<br/>";
    echo db2_conn_errormsg ();
    exit ();
}

//Prepare the stmt
$stmt1 = db2_prepare ( $conn_resource, $sql1 );

//Execute the prepared statement
if (! db2_execute ( $stmt1 )) {
    echo 'The db2 execute failed. ';
    echo 'SQLSTATE value: ' . db2_stmt_error ();
    echo ' Message: ' . db2_stmt_errormsg ();
    exit ();
}

//Loop through all rows, adding a third field
while ( $row1 = &db2_fetch_array ( $stmt1 ) ) {
    $row1[2] = "TEST";
}

//Reset stmt or array back to first record
//??

//Print results
echo "<table border=1>";
while ( $row = db2_fetch_array ( $stmt1 ) ) {
    echo "<tr>";
    echo "  <td>" . $row[0] . "</td>";
    echo "  <td>" . $row[1] . "</td>";
    echo "  <td>" . $row[2] . "</td>";
    echo "</tr>";
}
echo "</table>";

?>

我不認為這是可能的。 但無論如何,嘗試這樣做並不是一個令人信服的理由。

把事情簡單化。 只是第一次構建一個數組。

$rows = array();
//Loop through all rows, adding a third field
while ( $row = db2_fetch_array ( $stmt1 ) ) {
    $row[2] = "TEST";
    $rows[] = $row;
}
db2_free_result($stmt1);

//Print results
echo "<table border=1>";
foreach($rows as $row) {
    echo "<tr>";
    echo "  <td>" . $row[0] . "</td>";
    echo "  <td>" . $row[1] . "</td>";
    echo "  <td>" . $row[2] . "</td>";
    echo "</tr>";
}
echo "</table>";

在最壞的情況下,這將在構建陣列時暫時加倍內存使用量。

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