C++ OpenGL 立方體未顯示在屏幕上

Question

我最近一直在嘗試將 OpenGL 與 C++ 一起使用，並且在嘗試用照明渲染立方體時遇到了一個問題，但它似乎沒有出現，我相信這是由於某種剪裁錯誤。

這是我的代碼。 初始化function：

glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glEnable(GL_DEPTH_TEST);
glEnable(GL_COLOR_MATERIAL);
glEnable(GL_LIGHTING); //Enable lighting
glEnable(GL_LIGHT0); //Enable light #0
glEnable(GL_LIGHT1); //Enable light #1
glEnable(GL_NORMALIZE); //Automatically normalize normals

這是繪制代碼

 glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);

glTranslatef(0.0f, 0.0f, -8.0f);

//Add ambient light
GLfloat ambientColor[] = {0.2f, 0.2f, 0.2f, 1.0f}; //Color (0.2, 0.2, 0.2)
glLightModelfv(GL_LIGHT_MODEL_AMBIENT, ambientColor);

//Add positioned light
GLfloat lightColor0[] = {0.5f, 0.5f, 0.5f, 1.0f}; //Color (0.5, 0.5, 0.5)
GLfloat lightPos0[] = {4.0f, 0.0f, 8.0f, 1.0f}; //Positioned at (4, 0, 8)
glLightfv(GL_LIGHT0, GL_DIFFUSE, lightColor0);
glLightfv(GL_LIGHT0, GL_POSITION, lightPos0);

//Add directed light
GLfloat lightColor1[] = {0.5f, 0.2f, 0.2f, 1.0f}; //Color (0.5, 0.2, 0.2)
//Coming from the direction (-1, 0.5, 0.5)
GLfloat lightPos1[] = {-1.0f, 0.5f, 0.5f, 0.0f};
glLightfv(GL_LIGHT1, GL_DIFFUSE, lightColor1);
glLightfv(GL_LIGHT1, GL_POSITION, lightPos1);

glRotatef(Rotation, 0.0f, 1.0f, 0.0f);
glColor3f(1.0f, 1.0f, 0.0f);
glBegin(GL_QUADS);

//Front
glNormal3f(0.0f, 0.0f, 1.0f);
//glNormal3f(-1.0f, 0.0f, 1.0f);
glVertex3f(-1.5f, -1.0f, 1.5f);
//glNormal3f(1.0f, 0.0f, 1.0f);
glVertex3f(1.5f, -1.0f, 1.5f);
//glNormal3f(1.0f, 0.0f, 1.0f);
glVertex3f(1.5f, 1.0f, 1.5f);
//glNormal3f(-1.0f, 0.0f, 1.0f);
glVertex3f(-1.5f, 1.0f, 1.5f);

//Right
glNormal3f(1.0f, 0.0f, 0.0f);
//glNormal3f(1.0f, 0.0f, -1.0f);
glVertex3f(1.5f, -1.0f, -1.5f);
//glNormal3f(1.0f, 0.0f, -1.0f);
glVertex3f(1.5f, 1.0f, -1.5f);
//glNormal3f(1.0f, 0.0f, 1.0f);
glVertex3f(1.5f, 1.0f, 1.5f);
//glNormal3f(1.0f, 0.0f, 1.0f);
glVertex3f(1.5f, -1.0f, 1.5f);

//Back
glNormal3f(0.0f, 0.0f, -1.0f);
//glNormal3f(-1.0f, 0.0f, -1.0f);
glVertex3f(-1.5f, -1.0f, -1.5f);
//glNormal3f(-1.0f, 0.0f, -1.0f);
glVertex3f(-1.5f, 1.0f, -1.5f);
//glNormal3f(1.0f, 0.0f, -1.0f);
glVertex3f(1.5f, 1.0f, -1.5f);
//glNormal3f(1.0f, 0.0f, -1.0f);
glVertex3f(1.5f, -1.0f, -1.5f);

//Left
glNormal3f(-1.0f, 0.0f, 0.0f);
//glNormal3f(-1.0f, 0.0f, -1.0f);
glVertex3f(-1.5f, -1.0f, -1.5f);
//glNormal3f(-1.0f, 0.0f, 1.0f);
glVertex3f(-1.5f, -1.0f, 1.5f);
//glNormal3f(-1.0f, 0.0f, 1.0f);
glVertex3f(-1.5f, 1.0f, 1.5f);
//glNormal3f(-1.0f, 0.0f, -1.0f);
glVertex3f(-1.5f, 1.0f, -1.5f);

glEnd();

        SwapBuffers(hDC);

        Sleep (1);

---

在聽從 Keith 的建議后，我嘗試像這樣使用 gluLookAt：

void gluLookAt  (   10.0 , 10.0 , 10.0 , 1.5, -1.0, 1.5, 0.0, 0.0, 1.0 );

但我得到一個錯誤

|74|error: variable or field `gluLookAt' declared void|

Answer 1

您可能需要定義投影矩陣。

這可以通過例如gluLookAt()來完成

Answer 2

編輯后： gluLookAt是 function 就像glVertex3f等。 因此只需調用它來調用它：

gluLookAt(10.0 , 10.0 , 10.0 , 1.5, -1.0, 1.5, 0.0, 0.0, 1.0 );

請注意，這行代碼中沒有任何void ！

如果在這一行前面有一個void ，編譯器會看到一個名為gluLookAt的變量聲明，其類型為void初始化（構造），帶有一堆雙精度值。