通過 c# 中的反序列化將 xml 轉換為 List

Question

我有一個 xml 文件，我正在嘗試通過反序列化用數據填充我的列表。

我的 xml 在這里

<?xml version="1.0" ?>
<CustomerQueryRs>
    <CustomerRet>
        <ListID>6BE0000-1159990808</ListID>
        <Name>+ Blaine Bailey</Name>
        <FullName>+ Blaine Bailey</FullName>
        <Phone>866-855-0800</Phone>
    </CustomerRet>
    <CustomerRet>
        <ListID>9BA0000-1165353294</ListID>
        <Name>+ Brian Boyd</Name>
        <FullName>+ Brian Boyd</FullName>
        <Phone>203-245-1877</Phone>
    </CustomerRet>
        <CustomerRet>
        <ListID>9280000-1164147562</ListID>
        <Name>+ Brian Leahy</Name>
        <FullName>+ Brian Leahy</FullName>
        <Phone>508-341-0955</Phone>
    </CustomerRet>
</CustomerQueryRs>

在這里，我給出了我的完整代碼。 我只是不明白為什么我的代碼不起作用......我的代碼中缺少什么......它沒有給出錯誤但列表沒有被填充。 所以請告訴我我需要在代碼中糾正哪個區域。

[XmlTypeAttribute(AnonymousType = true)]
public class CustomersData
{
    [XmlArray(ElementName = "CustomerQueryRs")]
    [XmlArrayItem(ElementName = "CustomerRet")]
    public List<Customer> Customers { get; set; }

    public CustomersData()
    {
        Customers = new List<Customer>();
    }

}

public class Customer
{
    [XmlElement(ElementName = "ListID")]
    public string ListID { get; set; }

    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }

    [XmlElement(ElementName = "FullName")]
    public string FullName { get; set; }

    [XmlElement(ElementName = "Phone")]
    public string Phone { get; set; }
}

這是我的反序列化代碼

private object DeserialzeXml(string xml)
    {
        var xmlSer = new XmlSerializer(typeof(CustomersData), new XmlRootAttribute("CustomerQueryRs"));
        var stringReader = new StringReader(xml);
        return xmlSer.Deserialize(stringReader);
    }

請幫忙......

Answer 1

這應該有效：

[XmlElement("CustomerRet")]
public List<Customer> Customers { get; set; }

還有一個完整的例子：

[XmlTypeAttribute(AnonymousType = true)]
public class CustomersData
{
    [XmlElement("CustomerRet")]
    public List<Customer> Customers { get; set; }

    public CustomersData()
    {
        Customers = new List<Customer>();
    }
}

public class Customer
{
    [XmlElement(ElementName = "ListID")]
    public string ListID { get; set; }

    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }

    [XmlElement(ElementName = "FullName")]
    public string FullName { get; set; }

    [XmlElement(ElementName = "Phone")]
    public string Phone { get; set; }
}

class Program
{
    static void Main()
    {
        var xml = 
@"<?xml version=""1.0"" ?>
<CustomerQueryRs>
  <CustomerRet>
    <ListID>6BE0000-1159990808</ListID>
    <Name>+ Blaine Bailey</Name>
    <FullName>+ Blaine Bailey</FullName>
    <Phone>866-855-0800</Phone>
  </CustomerRet>
  <CustomerRet>
    <ListID>9BA0000-1165353294</ListID>
    <Name>+ Brian Boyd</Name>
    <FullName>+ Brian Boyd</FullName>
    <Phone>203-245-1877</Phone>
  </CustomerRet>
  <CustomerRet>
    <ListID>9280000-1164147562</ListID>
    <Name>+ Brian Leahy</Name>
    <FullName>+ Brian Leahy</FullName>
    <Phone>508-341-0955</Phone>
  </CustomerRet>
</CustomerQueryRs>";
        var serializer = new XmlSerializer(typeof(CustomersData), new XmlRootAttribute("CustomerQueryRs"));
        using (var stringReader = new StringReader(xml))
        using (var reader = XmlReader.Create(stringReader))
        {
            var result = (CustomersData)serializer.Deserialize(reader);
            Console.WriteLine(result.Customers[1].FullName);
        }
    }
}

Answer 2

用於將 xml 轉換為列表的可讀代碼

 string xmlString = System.IO.File.ReadAllText(@"C:\Users\user\Downloads\userDetail.xml");

 List<GridViewDetails> userDetail = (List<GridViewDetails>)ConvertXmlStringtoObject<List<GridViewDetails>>(xmlString);

  static T ConvertXmlStringtoObject<T>(string xmlString)
        {
            T classObject;

            XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));
            using (StringReader stringReader = new StringReader(xmlString))
            {
                classObject = (T)xmlSerializer.Deserialize(stringReader);
            }
            return classObject;
        }