我不明白為什么 string.size 返回它的作用

Question

long_string = <<EOS
It was the best of times,
It was the worst of times.
EOS

返回 53。為什么？ 空格算不算？ 即便如此。 我們如何得到 53？

這個怎么樣？

     def test_flexible_quotes_can_handle_multiple_lines
    long_string = %{
It was the best of times,
It was the worst of times.
}
    assert_equal 54, long_string.size
  end

  def test_here_documents_can_also_handle_multiple_lines
    long_string = <<EOS
It was the best of times,
It was the worst of times.
EOS
    assert_equal 53, long_string.size
  end

是這種情況嗎，因為 %{ 案例將每個/n視為一個字符，並且在第一行之前被認為是一個，在末尾一個，然后在第二行末尾，而在EOS案例中只有一個在第一行之前和第一行之后？ 也就是說，為什么前者是54，而后者是53？

Answer 1

為了：

long_string = <<EOS
It was the best of times,
It was the worst of times.
EOS

String is:
"It was the best of times,\nIt was the worst of times.\n"

It was the best of times, => 25
<newline> => 1
It was the worst of times. => 26
<newline> => 1
Total = 25 + 1 + 26 + 1 = 53

和

long_string = %{
It was the best of times,
It was the worst of times.
}

String is:
"\nIt was the best of times,\nIt was the worst of times.\n"
#Note leading "\n"

這個怎么運作：

在<<EOS的情況下，它后面的行是字符串的一部分。 <<之后的所有文本與<<位於同一行，並且到該行的末尾將是確定字符串何時結束的“標記”的一部分（在這種情況下，一行上的EOS本身與<<EOS ）。

在%{...}的情況下，它只是用於代替"..."的不同分隔符。 因此，當字符串在%{之后的新行開始時，該換行符是字符串的一部分。

試試這個例子，你會看到%{...}與"..."的工作方式相同：

a = "
It was the best of times,
It was the worst of times.
"
a.length # => 54

b = "It was the best of times,
It was the worst of times.
"
b.length # => 53