Python：捕獲異常並重復代碼

Question

我有以下代碼：

import imaplib, re
import os
import time

conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("ddd", "dddd")

while(True):
        unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
        print unreadCount

        if int(unreadCount) > 10:
                print "restarting..."

        time.sleep(50)

有時會失去連接並停止工作。 如何捕獲異常並在每次中斷時重新啟動代碼？

謝謝

Answer 1

import imaplib, re
import os
import time

while True:
    try:
        conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
        conn.login("ddd", "dddd")

        while True :
                unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
                print unreadCount

                if int(unreadCount) > 10:
                        print "restarting..."

                time.sleep(50)
    except HypotheticalException:
        pass

Answer 2

使用try ...

try:
   unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
   if int(unreadCount) > 10:
            print "restarting..."

    time.sleep(50)
except Exception:
  pass

Answer 3

嘗試這個：

import imaplib, re
import os
import time


for n in range(3):
try:
    conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
    conn.login("ddd", "dddd")
    while(True):
        unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
        print unreadCount

        if int(unreadCount) > 10:
            print "restarting..."

        time.sleep(50)
    break
except Exception, e:
    if n == 2:
        print >>sys.stderr, "Failure During processing, restarting..."
        print >>sys.stderr, e

您可以將n設置為要允許的嘗試次數。

編輯：嗯，進一步細讀之后，看來我弄錯了您的代碼。 我已經編輯並修復了我的版本。 您將需要調整和編輯while循環，因為我不太確定自己在做什么。

編輯2：由於您需要重新連接並再試一次，所以我將conn部分移到了try塊中。