Python：捕获异常并重复代码

Question

我有以下代码：

import imaplib, re
import os
import time

conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("ddd", "dddd")

while(True):
        unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
        print unreadCount

        if int(unreadCount) > 10:
                print "restarting..."

        time.sleep(50)

有时会失去连接并停止工作。 如何捕获异常并在每次中断时重新启动代码？

谢谢

Answer 1

import imaplib, re
import os
import time

while True:
    try:
        conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
        conn.login("ddd", "dddd")

        while True :
                unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
                print unreadCount

                if int(unreadCount) > 10:
                        print "restarting..."

                time.sleep(50)
    except HypotheticalException:
        pass

Answer 2

使用try ...

try:
   unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
   if int(unreadCount) > 10:
            print "restarting..."

    time.sleep(50)
except Exception:
  pass

Answer 3

尝试这个：

import imaplib, re
import os
import time


for n in range(3):
try:
    conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
    conn.login("ddd", "dddd")
    while(True):
        unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
        print unreadCount

        if int(unreadCount) > 10:
            print "restarting..."

        time.sleep(50)
    break
except Exception, e:
    if n == 2:
        print >>sys.stderr, "Failure During processing, restarting..."
        print >>sys.stderr, e

您可以将n设置为要允许的尝试次数。

编辑：嗯，进一步细读之后，看来我弄错了您的代码。 我已经编辑并修复了我的版本。 您将需要调整和编辑while循环，因为我不太确定自己在做什么。

编辑2：由于您需要重新连接并再试一次，所以我将conn部分移到了try块中。