[英]Deserialize XML Array of Elements
所以,反序列化工作但是我有一些 xml 像這樣:
<File>
<Stuff>stuff</Stuff>
<Devices>
<Device Type="1">
<Number>1</Number>
</Device>
<Device Type="2">
<Number>2</Number>
</Device>
</Devices>
</File>
當它到達設備陣列時……第一個設備是唯一一個填充到 object 中的設備。 以下是課程:
XmlSerializer deserializer;
XmlRootAttribute xRoot = new XmlRootAttribute();
FileStream stream = new FileStream(CONFIG_PATH, FileMode.Open);
XmlReader reader = new XmlTextReader(stream);
// Details configuration area.
xRoot.ElementName = "File";
xRoot.IsNullable = true;
deserializer = new XmlSerializer(typeof(File), xRoot);
Configuration = (File)deserializer.Deserialize(reader);
[Serializable()]
[XmlRoot(ElementName = "File", IsNullable = true)]
public sealed class File
{
[XmlElement("Devices")]
public Devices Devices { get; set; }
}
// <summary>
/// Configuration device elements.
/// </summary>
[Serializable()]
[XmlRoot("Devices", IsNullable = true)]
public sealed class Devices
{
[XmlElement("Device")]
public DeviceElements[] DeviceElements { get; set; }
}
/// <summary>
/// Configuration Devices.
/// </summary>
[Serializable()]
[XmlRoot("Device", IsNullable = true)]
public sealed class DeviceElements
{
[XmlAttribute("Type")]
public string DeviceType { get; set; }
[XmlElement("Number")]
public int DeviceNumber { get; set; }
}
同樣,只填充了第一個設備,我玩過 XmlArray 和 XmlArrayItem 但是他們都沒有給我第一個值。 有什么建議么?
你一定在另一個地方做錯了什么。 只需使用 XML 的Devices
部分:
<Devices>
<Device Type="1">
<Number>1</Number>
</Device>
<Device Type="2">
<Number>2</Number>
</Device>
</Devices>
我能夠成功地反序列化具有多個DeviceElements
子級的Devices
class 實例,因為上面的類使用與上一個問題中使用的代碼類似的代碼:
FileStream stream = new FileStream("test.xml", FileMode.Open);
XmlReader reader = new XmlTextReader(stream);
XmlSerializer deserializer = new XmlSerializer(typeof(Devices));
var devicesResult = (Devices)deserializer.Deserialize(reader);
編輯:
使用完整的 XML:
<File>
<Stuff>stuff</Stuff>
<Devices>
<Device Type="1">
<Number>1</Number>
</Device>
<Device Type="2">
<Number>2</Number>
</Device>
</Devices>
</File>
這成功地為我反序列化:
FileStream stream = new FileStream("test.xml", FileMode.Open);
XmlReader reader = new XmlTextReader(stream);
XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "File";
xRoot.IsNullable = true;
XmlSerializer deserializer = new XmlSerializer(typeof(File), xRoot);
var fileResult = (File)deserializer.Deserialize(reader);
On a side note - you probably shouldn't name your class the same as one already in the .NET framework ( System.IO.File
), also in above code example setting the Xml root is not required since you use the same name anyway,把這個留在外面:
FileStream stream = new FileStream("test.xml", FileMode.Open);
XmlReader reader = new XmlTextReader(stream);
XmlSerializer deserializer = new XmlSerializer(typeof(File));
var fileResult = (File)deserializer.Deserialize(reader);
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