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當teed時,python無法分離進程。 如何跨越后台進程並毫無等待退出?

[英]python unable to detach process when teed. How to span background process and exit with no wait?

我從一個簡單的測試用例開始:

cat foo2.py
#!/usr/bin/python
import subprocess, sys, os

def alert():
    subprocess.Popen ("xterm &", shell=True, stdin=None, stdout=None, stderr=None, close_fds=True)

if __name__ == "__main__":

   print "hello"
   alert ()
   os._exit (0)

當我在命令行上定期運行該代碼時,它可以工作:

./foo2.py

返回unix提示符,xterm在后台運行。

但是,當我用tee運行該代碼時

./foo2.py | tee my.log

在關閉xterm之前,我沒有得到unix提示符。

如何讓python腳本退出,但是讓xterm在后台運行?

我已經看到: Python產生子子進程,分離和退出以及那里提到的activestate配方。 我已經使用該代碼創建了一個簡單的測試用例,它只是在后台打開一個xterm:

cat foo.py
#!/usr/bin/python
import subprocess, sys, os

def alert():
    subprocess.Popen ("xterm &", shell=True, stdin=None, stdout=None, stderr=None)

def createDaemon():
   """Detach a process from the controlling terminal and run it in the
   background as a daemon.
   """
   try:
      pid = os.fork()   # Fork a first child.
   except OSError, e:
      raise Exception, "%s [%d]" % (e.strerror, e.errno)

   if (pid == 0):   # The first child.
      os.setsid()
      try:
         pid = os.fork()    # Fork a second child.
      except OSError, e:
         raise Exception, "%s [%d]" % (e.strerror, e.errno)

      if (pid == 0):    # The second child.
     alert () 
      else:
         os._exit(0)    # Exit parent (the first child) of the second child.
   else:
      os._exit(0)   # Exit parent of the first child.

   # Close all open file descriptors.  This prevents the child from keeping
   import resource      # Resource usage information.
   maxfd = resource.getrlimit(resource.RLIMIT_NOFILE)[1]
   if (maxfd == resource.RLIM_INFINITY):
      maxfd = 1024

   # Iterate through and close all file descriptors.
   for fd in range(0, maxfd):
      try:
         os.close(fd)
      except OSError:   # ERROR, fd wasn't open to begin with (ignored)
         pass

   os.open(REDIRECT_TO, os.O_RDWR)  # standard input (0)
   os.dup2(0, 1)            # standard output (1)
   os.dup2(0, 2)            # standard error (2)

   return(0)

if __name__ == "__main__":

   print "hello"
   retCode = createDaemon()

   sys.exit (0)

當我在命令行上定期運行該代碼時,它可以工作:

./foo.py

返回unix提示符,xterm在后台運行。

但是,當我用tee運行該代碼時

./foo.py | tee my.log

在關閉xterm之前,我沒有得到unix提示符。

如何讓python腳本退出,但是讓xterm在后台運行?

運行nohup xterm & (以便進程解耦)

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