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在F#中編寫相互遞歸函數時出現問題

[英]Problem writing mutually recursive function in F#

我正在翻譯來自Little Mler的對此數據類型進行操作的函數

type sexp<'T> = 
    An_Atom of 'T
    | A_slist of slist<'T>
and 
    slist<'T> = 
    Empty
    | Scons of sexp<'T> * slist<'T>

功能

// occurs_in_slist : aVal slist -> int
// checks the number of occurrence for aVal in slist

let rec occurs_in_slist =
    function
    _, Empty-> 0
   | (aVal : 'T), Scons(aSexp, (aSlist : 'T)) -> 
    occurs_in_sexp (aVal, aSexp) + occurs_in_slist (aVal, aSlist)
and
   aVal, An_Atom (bVal) ->  if (aVal = bVal) then 1 else 0
   |  (aVal , A_slist(aSlist)) -> occurs_in_slist (aval, aSlist)

但是,第二個功能卻出現此錯誤

error FS0010: Unexpected symbol '->' in binding. Expected '=' or other token.

在函數定義中,您使用了and關鍵字定義了一組相互遞歸的函數,但是僅給第一個函數指定了名稱。 它的后預計其它功能的名稱and這就是為什么你得到錯誤。 不幸的是,您忽略了這一點。

我相信這是您想要做的:

let rec occurs_in_slist = function
  | _        , Empty -> 0
  | aVal : 'T, Scons(aSexp, aSlist : slist<'T>) -> 
        occurs_in_sexp (aVal, aSexp) + occurs_in_slist (aVal, aSlist)
and occurs_in_sexp = function
  | aVal : 'T, An_Atom(bVal) -> if (aVal = bVal) then 1 else 0
  | aVal     , A_slist(aSlist) -> occurs_in_slist (aVal, aSlist)

盡管我覺得這里更合適的返回類型應該是bool

let rec occurs_in_slist = function
  | _        , Empty -> false
  | aVal : 'T, Scons(aSexp, aSlist : slist<'T>) -> 
        occurs_in_sexp (aVal, aSexp) || occurs_in_slist (aVal, aSlist)
and occurs_in_sexp = function
  | aVal : 'T, An_Atom(bVal) -> aVal = bVal
  | aVal     , A_slist(aSlist) -> occurs_in_slist (aVal, aSlist)

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