從查詢正則表達式中提取值

Question

我需要提取條件（WHERE）的值並進行正則表達式，但我無法正確獲取值。

//Patherns
$regex  = "/([a-zA-Z_]+)\s([\<\=\>\s]{0,4})\s+(\".*\")/";

//values ​​to be extracted
$string = 'idCidade >= "bla" OR idEstado="2" and idPais="3"'; 

//regex function
preg_match_all(
    $regex,
    $string,
    $output
);

//displays the result
echo '<pre>';print_r($output);



//incorrect output
Array
(
   [0] => Array
    (
        [0] => idCidade >= "bla" OR idEstado="2" and idPais="3"
    )

   [1] => Array
    (
        [0] => idCidade 
    )

   [2] => Array
    (
        [0] => >= 
    )

   [3] => Array
    (
        [0] => "bla" OR idEstado="2" and idPais="3"
    )
)

我需要正則表達式將值導出到這樣的數組;

//correct output
Array
(
   [0] => Array
    (
        [0] => idCidade >= "bla" OR idEstado="2" and idPais="3"
    )

   [1] => Array
    (
        [0] => idCidade
        [1] => idEstado
        [2] => idPais
    )

   [2] => Array
    (
        [0] => >=
        [1] => =
        [2] => =
    )

   [3] => Array
    (
        [0] => "bla"
        [1] => "2"
        [2] => "3"
    )
   [4] => Array
    (
        [0] => "OR"
        [1] => "AND"
        [2] => ""
    )
)

Answer 1

您的錯誤可能是匹配過多的.* 。 您需要添加一個問號使它“不舒服”： .*?

但是我建議使用此正則表達式：

'/(OR|AND)?\s*(\w+)\s*([<=>!]+)\s*("[^"]*"|\'[^\']*\'|\d+)/i'

這首先匹配布爾連接器，也可以選擇匹配，因此您將獲得：

[1] => Array
    (
        [0] => 
        [1] => OR
        [2] => and
    )

[2] => Array
    (
        [0] => idCidade
        [1] => idEstado
        [2] => idPais
    )

[3] => Array
    (
        [0] => >=
        [1] => =
        [2] => =
    )

[4] => Array
    (
        [0] => "bla"
        [1] => "2"
        [2] => "3"
    )

我也使它適用於SQL兼容的字符串和小數。 但這僅僅是正則表達式的一項工作。 建議使用真正的解析器。 （盡管我不知道您的用例。）

Answer 2

嘗試這個。 這將輸出您需要的確切結果。

<?php  //Patherns
$regex  = '/([a-zA-Z_]+)\s*([>=<]*)\s*"([^"]*)"\s*(or|and)*/i';

//values to be extracted
$string = 'idCidade >= "bla" OR idEstado="2" and idPais="3"';

//regex function
preg_match_all(
    $regex,
    $string,
    $output
);

//displays the result
echo '<pre>';print_r($output);