周末退貨問題

Question

所以我有這個：

$start_date = date('Y-m-d',strtotime('Friday 17:00'));
$end_date = date('Y-m-d',strtotime("+2 days", strtotime('Friday')));
$conditions['scope'] = " (event_start_date BETWEEN CAST('$start_date' AS DATE) AND CAST('$end_date' AS DATE)) OR (event_end_date BETWEEN CAST('$end_date' AS DATE) AND CAST('$start_date' AS DATE))";

我希望輸出下一個周末的日期（星期五在1700-周日），直到我到星期五為止，然后開始顯示下一個周末。

如何顯示當前周末到星期日結束，然后再顯示下一個周末？

Answer 1

$end_date = date('Y-m-d', strToTime('this Sunday'));

這是strToTime的相對日期的參考。

Answer 2

$end_date = date('Y-m-d',strtotime('Sunday'));
$start_date = date('Y-m-d',strtotime($end_date . ' -2 days '));