周末退货问题

Question

所以我有这个：

$start_date = date('Y-m-d',strtotime('Friday 17:00'));
$end_date = date('Y-m-d',strtotime("+2 days", strtotime('Friday')));
$conditions['scope'] = " (event_start_date BETWEEN CAST('$start_date' AS DATE) AND CAST('$end_date' AS DATE)) OR (event_end_date BETWEEN CAST('$end_date' AS DATE) AND CAST('$start_date' AS DATE))";

我希望输出下一个周末的日期（星期五在1700-周日），直到我到星期五为止，然后开始显示下一个周末。

如何显示当前周末到星期日结束，然后再显示下一个周末？

Answer 1

$end_date = date('Y-m-d', strToTime('this Sunday'));

这是strToTime的相对日期的参考。

Answer 2

$end_date = date('Y-m-d',strtotime('Sunday'));
$start_date = date('Y-m-d',strtotime($end_date . ' -2 days '));