[英]I have created a dynamic ListView - how do I connect it to my XML layout file?
大家好,謝謝您對此的關注。 我使用Android的開發人員指南創建了動態ListView。 當前,ListView活動似乎可以在屏幕上顯示自己,而無需XML文件或setContentView ...這是一個問題。
我想使用XML布局,所以我可以將其他視圖添加到屏幕上,而不是將整個活動專門用於顯示列表。 我創建了一個XML布局,其中包含一個空白的ListView等,我希望我的列表進入分配的空間...所以我的問題是:如何獲取ListActivity以使用布局XML文件?
public class MainList extends ListActivity {
static SharedPreferences statusSettings;
String jsonString;
static JSONObject json;
static JSONArray arrayTest;
static int bob = 3;
@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
// TODO Auto-generated method stub
super.onListItemClick(l, v, position, id);
try {
JSONObject e = arrayTest.getJSONObject(position);
Intent intent = new Intent();
intent.putExtra("clientName", e.getString("proj_name"));
intent.putExtra("clientAddress", e.getString("c_address"));
intent.putExtra("clientComments", e.getString("comments"));
intent.putExtra("clientOrder", e.getString("order"));
intent.setClass(MainList.this, ClientDetails.class);
MainList.this.startActivity(intent);
} catch (JSONException e) {
// TODO Auto-generated catch block
Log.e("JSON", "Problem creating object from array!");
e.printStackTrace();
}
}
private static class EfficientAdapter extends BaseAdapter {
private LayoutInflater mInflater;
public EfficientAdapter(Context context) {
// Cache the LayoutInflate to avoid asking for a new one each time.
mInflater = LayoutInflater.from(context);
}
public int getCount() {
return arrayTest.length();
}
public Object getItem(int position) {
return position;
}
public long getItemId(int position) {
return position;
}
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder;
if (convertView == null) {
convertView = mInflater.inflate(R.layout.mainlist, null);
holder = new ViewHolder();
holder.textName = (TextView) convertView.findViewById(R.id.tvMainName);
holder.textAddress = (TextView) convertView.findViewById(R.id.tvMainAddress);
convertView.setTag(holder);
} else {
holder = (ViewHolder) convertView.getTag();
}
JSONObject e;
try {
e = arrayTest.getJSONObject(position);
holder.textName.setText(e.getString("proj_name"));
holder.textAddress.setText(e.getString("c_address"));
switch (statusSettings.getInt(e.getString("order"), 0)){
case 1:
convertView.setBackgroundColor(0x00000000);
break;
case 2:
if(bob == 3){
convertView.setBackgroundColor(0xFFFF6600);
bob = 5;
}
break;
case 3:
convertView.setBackgroundColor(0xFF00CC00);
break;
case 4:
convertView.setBackgroundColor(0xFFCC0000);
break;
}
} catch (JSONException e1) {
// TODO Auto-generated catch block
Log.e("JSON", "Couldn't put one of JSON arrays into object");
e1.printStackTrace();
}
return convertView;
}
static class ViewHolder {
TextView textName;
TextView textAddress;
}
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
jsonString = getIntent().getExtras().getString("jsonString");
try {
json = new JSONObject(jsonString);
arrayTest = json.getJSONArray("client_list");
} catch (JSONException e) {
// TODO Auto-generated catch block
Log.e("JSON", "Couldn't create the JSON Array");
e.printStackTrace();
}
setListAdapter(new EfficientAdapter(this));
}
@Override
protected void onResume() {
// TODO Auto-generated method stub
super.onResume();
bob = 3;
statusSettings = getSharedPreferences("status", 0);
setListAdapter(new EfficientAdapter(this));
}
}
XML檔案:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<ListView
android:id="@+id/list"
android:layout_width="match_parent"
android:layout_height="wrap_content" android:layout_weight="1">
</ListView>
<Button
android:id="@+id/button1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button" />
</LinearLayout>
事實是,他們無需使用任何XML布局即可創建它-我尚不完全了解該怎么做,但我認為它與LayoutInflater有關。 我試過了:convertView = mInflater.inflate(R.id.list,null);
而不是convertView = mInflater.inflate(R.layout.mainlist,null);
我放置了setContentView(R.layout.test); 在我的onCreate中...但是沒有用。 您提供的任何幫助將不勝感激,謝謝!
這很簡單。 我已經快速生成了一些代碼供您參考。
public class ListandtextActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
final String [] str = {"ONE","TWO","THREE"};
final ListView lv = (ListView) findViewById(R.id.listView1);
final TextView tv = (TextView)findViewById(R.id.tv1);
lv.setAdapter(new ArrayAdapter<Object>(getApplicationContext(), android.R.layout.simple_list_item_1, str));
lv.setOnItemClickListener(new OnItemClickListener(){
@Override
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {
tv.setText("You Clicked Something");
}
});
}
}
在您的XML中
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<TextView
android:id="@+id/tv1"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="@string/hello" />
<ListView
android:id="@+id/listView1"
android:layout_width="match_parent"
android:layout_height="wrap_content" >
</ListView>
</LinearLayout>
隨時詢問您是否有任何疑問。
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