簡體   English   中英

使所有頁面都以不同的html結構表示來自不同表的數據

[英]Make everything page representing data from different tables in different html structure

我想在我的網站上創建一個“一切”頁面,其中將顯示所有用戶活動。 因此,我需要從兩個表“ images”和“ user_favorites”中制作sql並將其全部輸出到此html設計中

我的表結構:

使用者

id

圖片

id
user_id
image
description
date

user_favorites

id
date

我有這個SQL查詢

function users_everything($user_id)
{
    $sql = "SELECT 
                i.description as text, 
                UNIX_TIMESTAMP(i.date) as image_date, 
                COALESCE ( imgcount.cnt, 0 ) as comments,
                fav.id as favorite_id,
                r.image as favorited_image,
                u2.username as favorite_user,
                t.image as favorite_user_image                                                            
            FROM users u
            LEFT JOIN images i ON i.user_id = u.id
            LEFT JOIN images p ON p.id = (SELECT b.id FROM images AS b where u.id = b.user_id ORDER BY b.id DESC LIMIT 1)
            LEFT JOIN (SELECT image_id, COUNT(*) as cnt FROM commentaries GROUP BY image_id  ) imgcount ON i.id = imgcount.image_id

            LEFT JOIN user_favorites fav ON fav.user_id = u.id                
            LEFT JOIN images r ON r.id = fav.image_id
            LEFT JOIN users u2 ON u2.id = r.user_id                                
            LEFT JOIN images t ON t.id = (SELECT b.id FROM images AS b where u2.id = b.user_id ORDER BY b.id DESC LIMIT 1)                                                                

            WHERE i.user_id = ?
            ";

    $query = $this->db->query($sql, $user_id);

    return $query->result_array();
}

我的“圖像”表有1條記錄,“ user_follow”有2條記錄,但是如果我這樣做,它將返回兩個收藏夾,並且復制了兩個圖像(圖像)。

我不會像所有頁面那樣制作東西,然后再將不同頁面的數據呈現給不同的html結構。 我想你有經驗,可以幫助我

您需要將平面記錄數組轉換為樹結構,其中每個圖像都包含一個收藏夾列表。 就像是:

$images = array();
foreach($everything_list as $item)
{
    // Check to see if already encountered this image
    $imageId = $item['image_id'];
    if (!isset($images[$imageId]))
    {
        // New image
        $image = array();

        // Do this for each image attribute
        $image['image_id'] = $item['image_id'];

        $image['favorites'] = array();
        $images[$imageId] = $image;
    }
    // Add Favorite
    $favorite = array();

    // Do this for each favorite attribute
    $favorite['favorite_id'] = $item['favorite_id'];

    $images[$imageId]['favorites'][] = $favorite;
}
print_r($images);

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM