[英]Sql Pivot table with two cross tab and multiple columns
我正在嘗試構建一個包含兩個交叉表和多列的表。 到目前為止,我有這個,當我運行它
create table test2(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int)
insert into test2 values ('Austin', 'African-American', 'male', 21)
insert into test2 values ('Austin', 'Asian', 'female', 22)
insert into test2 values ('Austin', 'Caucasian', 'male', 23)
insert into test2 values ('Austin', 'Hispanic', 'female', 24)
insert into test2 values ('Austin', 'African-American', 'Unknown', 25)
insert into test2 values ('Austin', 'Asian', 'male', 26)
insert into test2 values ('Austin', 'Caucasian', 'female', 27)
insert into test2 values ('Austin', 'Hispanic', 'Unknown', 28)
insert into test2 values ('Austin', 'Asian', 'male', 29)
insert into test2 values ('Austin', 'Caucasian', 'female', 31)
insert into test2 values ('Dallas', 'Hispanic', 'Unknown', 32)
insert into test2 values ('Dallas', 'African-American', 'male', 33)
insert into test2 values ('Dallas', 'Asian', 'female', 34)
insert into test2 values ('Dallas', 'Caucasian', 'Unknown', 35)
insert into test2 values ('Dallas', 'Hispanic', 'male', 500)
insert into test2 values ('Dallas', 'African-American', 'female', 36)
insert into test2 values ('Dallas', 'Asian', 'Unknown', 37)
insert into test2 values ('Dallas', 'Caucasian', 'male', 38)
insert into test2 values ('Dallas', 'Hispanic', 'female', 39)
insert into test2 values ('Dallas', 'African-American', 'Unknown', 41)
insert into test2 values ('Houston', 'Asian', 'male', 42)
insert into test2 values ('Houston', 'Caucasian', 'female', 43)
insert into test2 values ('Houston', 'Hispanic', 'Unknown', 44)
insert into test2 values ('Houston', 'African-American', 'male', 45)
insert into test2 values ('Houston', 'Asian', 'female', 46)
insert into test2 values ('Houston', 'Caucasian', 'Unknown', 47)
insert into test2 values ('Houston', 'Hispanic', 'male', 48)
insert into test2 values ('Houston', 'African-American', 'female', 49)
insert into test2 values ('Houston', 'Asian', 'Unknown', 51)
insert into test2 values ('Houston', 'Caucasian', 'male', 52)
SELECT *
FROM
(
SELECT a.city, a.sex
FROM [AdventureWorksDW].[dbo].[test2] a
) p
PIVOT
(
COUNT (sex)
FOR sex
IN ([male], [female], [Unknown])
) AS pvt
我明白了
(來源: realestateagenthealthinsurance.com )
但我需要的是這個,頂部有兩個交叉標簽,多個列有一個選項。
(來源: realestateagenthealthinsurance.com )
這可能是通過樞軸或任何其他解決方案嗎? 提前致謝
您可以為3個年齡組中的每個年齡組運行單獨的PIVOT查詢,然后將結果外部連接到城市和性別的查詢:
WITH DataKeys AS (
select distinct city, sex
from test2),
Data20to29 AS (
SELECT *
FROM(SELECT * FROM test2 WHERE age between 20 and 29
) AS Age20to29
PIVOT (COUNT(age)
FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
) as Data20to29),
Data30to39 AS (
SELECT *
FROM(SELECT * FROM test2 WHERE age between 30 and 39
) AS Age30to39
PIVOT (COUNT(age)
FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
) as Data30to39),
Data40to49 AS (
SELECT *
FROM(SELECT * FROM test2 WHERE age between 40 and 49
) AS Age40to49
PIVOT (COUNT(age)
FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
) as Data40to49)
SELECT SELECT k.city, k.sex,
d20.[African-American], d20.Asian, d20.Caucasian, d20.Hispanic,
d30.[African-American], d30.Asian, d30.Caucasian, d30.Hispanic,
d40.[African-American], d40.Asian, d40.Caucasian, d40.Hispanic
FROM DataKeys k LEFT JOIN Data20to29 d20 ON d20.city = k.city AND d20.sex = k.sex
LEFT JOIN Data30to39 d30 ON d30.city = k.city AND d30.sex = k.sex
LEFT JOIN Data40to49 d40 ON d40.city = k.city AND d40.sex = k.sex
ORDER BY k.city, k.sex
WITH T AS (
SELECT A.city,
A.sex,
CASE
WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
END AS age_range_race
FROM @test2 AS A
)
SELECT *
FROM T
PIVOT( COUNT(age_range_race) FOR age_range_race
IN(
[20-30_African-American],
[20-30_Asian],
[20-30_Caucasian],
[20-30_Hispanic],
[31-40_African-American],
[31-40_Asian],
[31-40_Caucasian],
[31-40_Hispanic],
[41-50_African-American],
[41-50_Asian],
[41-50_Caucasian],
[41-50_Hispanic]
)
) AS P
ORDER BY city, sex
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