Linq 中的 Row_number 超過（按 xxx 分區）？

Question

我有一個DataTable具有的結構和數據：

id |   inst   |   name
------------------------
 1 |  guitar  |  john
 2 |  guitar  |  george
 3 |  guitar  |  paul
 4 |  drums   |  ringo
 5 |  drums   |  pete

我可以通過以下方式檢索記錄：

IEnumerable <Beatle>...

class Beatle
{
  int id;
  string inst;
  string name;
}

我想了解演奏不同樂器的人的內部順序。 在 MSSQL 中我會使用

SELECT 
    *
    ,Row_Number() OVER (PARTITION BY inst ORDER BY id) AS rn
FROM Beatles

此查詢返回

id |   inst   |   name  | rn
-----------------------------
 1 |  guitar  |  john   | 1
 2 |  guitar  |  george | 2
 3 |  guitar  |  paul   | 3
 4 |  drums   |  ringo  | 1
 5 |  drums   |  pete   | 2

題：
我怎樣才能在Linq 中做到這一點？

Answer 1

試試這個襯墊：

var o = beatles
    .OrderBy( x => x.id )
    .GroupBy( x => x.inst )
    .Select( group => new { Group = group, Count = group.Count() } )
    .SelectMany( groupWithCount =>
        groupWithCount.Group.Select( b => b)
        .Zip(
            Enumerable.Range( 1, groupWithCount.Count ),
            ( j, i ) => new { j.inst, j.name, RowNumber = i }
        )
    );

foreach (var i in o)
{
    Console.WriteLine( "{0} {1} {2}", i.inst, i.name, i.RowNumber );
}

輸出：

Guitar John 1
Guitar George 2
Guitar Paul 3
drums Ringo 1
drums Pete 2

Answer 2

B"H

我知道這是舊的。 但為什么解決方案不簡單呢？

var o = beatles.GroupBy(x => x.inst)
               .SelectMany(g =>
                   g.Select((j, i) => new { j.inst, j.name, rn = i + 1 })
               );

Answer 3

如果可能，另一個想法是使用視圖。

Answer 4

Linq to objects 的另一個解決方案是：

var result = beatles
            .GroupBy(g => g.inst)
            // PARTITION BY ^^^^
            .Select(c => c.OrderBy(o => o.id).Select((v, i) => new { i, v }).ToList())
            //                   ORDER BY ^^
            .SelectMany(c => c)
            .Select(c => new { c.v.id, c.v.inst, c.v.name, rn = c.i + 1 })
            .ToList();

[ C# Demo ]

Answer 5

正如@The_Smallest 指出的，LINQ 不支持行號。 不過，您可以通過以下方式獲得所需內容：

var grouped = beatles.OrderBy( x => x.id )
  .ToList()   // required because SelectMany below doesn't evaluate to SQL
  .GroupBy( x => x.inst );
var rns = grouped.ToDictionary( x => x.Key, x => 1 );
var result = grouped
  .SelectMany( x => x.Select( 
    y => new { inst = y.inst, name = y.name, rn = rns[y.inst]++ } ) );

Answer 6

有些人可能會發現在您的代碼中使用以獲得正確的索引很有用

.Select((item, i) => new { Item = item, Index = i })

Answer 7

另一種等效於 RANK() OVER (PARTITION BY "partitionBy" ORDER BY "orderBy" DESC) 的解決方案：

 DataTable Rank(DataTable dt, string partitionBy, string orderBy, int whichRank)
   {

        DataView dv = new DataView(dt);
        dv.Sort = partitionBy + ", " + orderBy + " DESC";

        DataTable rankDt = dv.ToTable();
        rankDt.Columns.Add("Rank");
        int rank = 1;

        for (int i = 0; i < rankDt.Rows.Count - 1; i++)
        {
            rankDt.Rows[i]["Rank"] = rank;
            DataRow thisRow = rankDt.Rows[i];
            DataRow nextRow = rankDt.Rows[i + 1];

            if (thisRow[partitionBy].ToString() != nextRow[partitionBy].ToString())
                rank = 1;
            else
                rank++;
        }

        DataView selectRankdv = new DataView(rankDt);
        selectRankdv.RowFilter = "rank = " + whichRank;
        return selectRankdv.ToTable();
  }

Answer 8

根據@Jon Comtois 的回答，如果您需要過濾掉特定的行號，您可以使用以下擴展方法；

    /// <summary>
    /// Groups and orders by the data partitioning and returns the list of data with provided rownumber
    /// It is the equivalent of SQL's ROW_NUMBER() OVER (PARTITION BY ... ORDER BY ...)
    /// </summary>
    /// <typeparam name="TSource">Source type</typeparam>
    /// <typeparam name="TGroupingKey">Generic type for grouping property</typeparam>
    /// <typeparam name="TOrderKey">Generic type for ordering property</typeparam>
    /// <param name="source">Source list to be partitioned</param>
    /// <param name="groupingProperty">Grouping property</param>
    /// <param name="orderProperty">Ordering property</param>
    /// <param name="orderByAsc">Order direction</param>
    /// <param name="rowNumber">Rows to be filtered out finally</param>
    /// <returns>Partitioned list</returns>
    public static List<TSource> FilterByPartitioning<TSource, TGroupingKey, TOrderKey>(this List<TSource> source, Func<TSource, TGroupingKey> groupingProperty, Func<TSource, TOrderKey> orderProperty, bool orderByAsc = true, int rowNumber = 1)
    {
        var orderedData = orderByAsc ? source.OrderBy(orderProperty) : source.OrderByDescending(orderProperty);

        return orderedData.GroupBy(groupingProperty)
            .Select(g => new { g, count = g.Count() })
            .SelectMany(t => t.g.Select(b => b)
                .Zip(Enumerable.Range(1, t.count), (source, i) => new { source, row = i }))
            .Where(x => x.row == rowNumber)
            .Select(x => x.source).ToList();
    }

    //Usage
    var result = myList.FilterByPartitioning(group => group.PropertyToGroup, order => order.PropertyToOrder, orderByAsc: false, rowNumber: 1);

Answer 9

https://github.com/jurioli/Applied

var result = data.GroupBy(a => new { a.inst }).AsPartition()
.Over(p => p.RowNumber(), (a, value) => new { a.inst, a.name, RowNumber = value })
.ToList();