[英]How write a file using StreamWriter in Windows 8?
在Windows-8中創建StreamWriter
對象時遇到麻煩,通常我只是創建一個實例,只是將字符串作為參數傳遞,但是在Windows 8中,我收到一條錯誤消息,指示它應該接收流,但是我注意到Stream是一個抽象類,有人知道如何編寫xml文件嗎?,順便說一句,我正在使用.xml,因為我想保存序列化的對象,還是有人知道如何將序列化的對象保存到文件中在Windows 8中?
有任何想法嗎?
當前使用Windows 8 Consumer Preview
碼:
StreamWriter sw = new StreamWriter("person.xml");
錯誤:
The best overloaded method match for 'System.IO.StreamWriter.StreamWriter(System.IO.Stream)' has some invalid arguments
除了使用StreamWriter之外,您還可以使用以下方法:
StorageFolder folder = ApplicationData.Current.LocalFolder;
StorageFile file = await folder.CreateFileAsync();
using (IRandomAccessStream fileStream = await file.OpenAsync(FileAccessMode.ReadWrite))
{
using (IOutputStream outputStream = fileStream.GetOutputStreamAt(0))
{
using (DataWriter dataWriter = new DataWriter(outputStream))
{
//TODO: Replace "Bytes" with the type you want to write.
dataWriter.WriteBytes(bytes);
await dataWriter.StoreAsync();
dataWriter.DetachStream();
}
await outputStream.FlushAsync();
}
}
您可以查看WinRTXamlToolkit庫中的StringIOExtensions類,以供示例使用。
編輯*
盡管以上所有方法都可以工作-它們是在WinRT中的FileIO
類可用之前編寫的,這簡化了上述解決方案解決的大多數常見情況,因為您現在可以調用await FileIO.WriteTextAsync(file, contents)
來將文本寫入文件,還有類似的讀取,寫入或追加字符串,字節,字符串列表或IBuffers
。
您可以創建一個可以在整個應用程序中使用的通用靜態方法,如下所示
private async Task<T> ReadXml<T>(StorageFile xmldata)
{
XmlSerializer xmlser = new XmlSerializer(typeof(List<myclass>));
T data;
using (var strm = await xmldata.OpenStreamForReadAsync())
{
TextReader Reader = new StreamReader(strm);
data = (T)xmlser.Deserialize(Reader);
}
return data;
}
private async Task writeXml<T>(T Data, StorageFile file)
{
try
{
StringWriter sw = new StringWriter();
XmlSerializer xmlser = new XmlSerializer(typeof(T));
xmlser.Serialize(sw, Data);
using (IRandomAccessStream fileStream = await file.OpenAsync(FileAccessMode.ReadWrite))
{
using (IOutputStream outputStream = fileStream.GetOutputStreamAt(0))
{
using (DataWriter dataWriter = new DataWriter(outputStream))
{
dataWriter.WriteString(sw.ToString());
await dataWriter.StoreAsync();
dataWriter.DetachStream();
}
await outputStream.FlushAsync();
}
}
}
catch (Exception e)
{
throw new NotImplementedException(e.Message.ToString());
}
}
寫xml只需使用
StorageFile file = await ApplicationData.Current.LocalFolder.CreateFileAsync("data.xml",CreationCollisionOption.ReplaceExisting);
await writeXml(Data,file);
並讀取xml使用
StorageFile file = await ApplicationData.Current.LocalFolder.GetFileAsync("data.xml");
Data = await ReadXml<List<myclass>>(file);
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