[英]Binary Search Tree in C# Implementation
class Node
{
public int data;
public Node left, right;
public Node(int data)
{
this.data = data;
left = null;
right = null;
}
}
class BinaryTreeImp
{
Node root;
static int count = 0;
public BinaryTreeImp()
{
root = null;
}
public Node addNode(int data)
{
Node newNode = new Node(data);
if (root == null)
{
root = newNode;
}
count++;
return newNode;
}
public void insertNode(Node root,Node newNode )
{
Node temp;
temp = root;
if (newNode.data < temp.data)
{
if (temp.left == null)
{
temp.left = newNode;
}
else
{
temp = temp.left;
insertNode(temp,newNode);
}
}
else if (newNode.data > temp.data)
{
if (temp.right == null)
{
temp.right = newNode;
}
else
{
temp = temp.right;
insertNode(temp,newNode);
}
}
}
public void displayTree(Node root)
{
Node temp;
temp = root;
if (temp == null)
return;
displayTree(temp.left);
System.Console.Write(temp.data + " ");
displayTree(temp.right);
}
static void Main(string[] args)
{
BinaryTreeImp btObj = new BinaryTreeImp();
Node iniRoot= btObj.addNode(5);
btObj.insertNode(btObj.root,iniRoot);
btObj.insertNode(btObj.root,btObj.addNode(6));
btObj.insertNode(btObj.root,btObj.addNode(10));
btObj.insertNode(btObj.root,btObj.addNode(2));
btObj.insertNode(btObj.root,btObj.addNode(3));
btObj.displayTree(btObj.root);
System.Console.WriteLine("The sum of nodes are " + count);
Console.ReadLine();
}
}
這是實現的代碼。代碼工作正常,但如果在displayTree函數中,我替換它
public void displayTree(Node root)
{
Node temp;
temp = root;
while(temp!=null)
{
displayTree(temp.left);
System.Console.Write(temp.data + " ");
displayTree(temp.right);
}
}
導致無限循環。 我不明白是什么導致了這一點。我想知道是否有更好的方法在C#中實現BST。
我不確定你為什么需要這個循環,但回答你的問題:
while(temp!=null)
{
displayTree(temp.left);
System.Console.Write(temp.data + " ");
displayTree(temp.right);
}
此代碼檢查temp
是否為null
,但它永遠不會變為null,因為在循環內部 ,您只對temp的葉子起作用。 這就是為什么你有一個無限循環。
你不需要while循環或temp
變量,讓遞歸為你做的工作:
public void displayTree(Node root)
{
if(root == null) return;
displayTree(root.left);
System.Console.Write(root.data + " ");
displayTree(root.right);
}
temp在開頭設置為root,之后它的值永遠不會改變
怎么樣重寫你的功能
public void displayTree(Node root)
{
if (root == null)
return;
displayTree(root.left);
Console.Write(...);
displayTree(root.right);
}
嘗試這個
public void displayTree(Node root)
{
Node temp;
temp = root;
if (temp != null)
{
displayTree(temp.left);
Console.WriteLine(temp.data + " ");
displayTree(temp.right);
}
}
我只是想你也可以使用遞歸來添加函數。 它可能看起來像這樣
private void Add(BinaryTree node, ref BinaryTree rootNode)
{
if (rootNode == null)
{
rootNode = node;
}
if (node.value > rootNode.value)
{
Add(node, ref rootNode.right);
}
if (node.value < rootNode.value)
{
Add(node, ref rootNode.left);
}
}
請參閱https://msdn.microsoft.com/en-us/library/ms379572%28v=vs.80%29.aspx 。 請參閱“遍歷BST的節點”部分中的示例代碼
另外......別忘了查看SortedDictionary等。他們可能已經准備好了你需要的BST! https://msdn.microsoft.com/en-us/library/f7fta44c.aspx
完整的二進制搜索樹...使用Code來檢查Tree是否平衡
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
namespace BinarySearchTree
{
public class Node
{
public Node(int iData)
{
data = iData;
leftNode = null;
rightNode= null;
}
public int data{get; set;}
public Node leftNode{get; set;}
public Node rightNode{get; set;}
};
public class Program
{
public static Node root = null;
public static void Main(string[] args)
{
//Your code goes here
Console.WriteLine("Hello, world!");
root = new Node(20);
InsertNode(root, new Node(10));
InsertNode(root, new Node(15));
InsertNode(root, new Node(13));
InsertNode(root, new Node(11));
InsertNode(root, new Node(12));
InsertNode(root, new Node(25));
InsertNode(root, new Node(22));
InsertNode(root, new Node(23));
InsertNode(root, new Node(27));
InsertNode(root, new Node(26));
if(CheckIfTreeIsBalanced(root))
{
Console.WriteLine("Tree is Balanced!");
}
else
{
Console.WriteLine("Tree is Not Balanced!");
}
PrintTree(root);
}
public static void PrintTree(Node root)
{
if(root == null) return;
Node temp = root;
PrintTree(temp.leftNode);
System.Console.Write(temp.data + " ");
PrintTree(temp.rightNode);
}
public static bool CheckIfTreeIsBalanced(Node root)
{
if(root != null)
{
if(root.leftNode != null && root.rightNode!= null)
{
if(root.leftNode.data < root.data && root.rightNode.data > root.data)
{
return CheckIfTreeIsBalanced(root.leftNode)&&CheckIfTreeIsBalanced(root.rightNode);
}
else
{
return false;
}
}
else if(root.leftNode != null)
{
if(root.leftNode.data < root.data)
{
return CheckIfTreeIsBalanced(root.leftNode);
}
else
{
return false;
}
}
else if(root.rightNode != null)
{
if(root.rightNode.data > root.data)
{
return CheckIfTreeIsBalanced(root.rightNode);
}
else
{
return false;
}
}
}
return true;
}
public static void InsertNode(Node root, Node newNode )
{
Node temp;
temp = root;
if (newNode.data < temp.data)
{
if (temp.leftNode == null)
{
temp.leftNode = newNode;
}
else
{
temp = temp.leftNode;
InsertNode(temp,newNode);
}
}
else if (newNode.data > temp.data)
{
if (temp.rightNode == null)
{
temp.rightNode = newNode;
}
else
{
temp = temp.rightNode;
InsertNode(temp,newNode);
}
}
}
}
}
輸出:
Hello, world!
Tree is Balanced!
10 11 12 13 15 20 22 23 25 26 27
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