在Python中將帶小數位的字符串列表轉換為整數

Question

example_list = ['21.48678', '21.46552', '21.45145', '21.43822',
                '21.42734', '21.41222', '21.40132', '21.37679']

我在將此列表從字符串轉換為整數時遇到麻煩，我也希望將其作為整數。 謝謝 ：）

Answer 1

最簡單的是

[int(float(x)) for x in your_list]

這將截斷所有數字

如果要四舍五入，請改用此方法

[int(float(x)+.5) for x in your_list]

Answer 2

首先轉換為float

>>> lst = ['21.48678', '21.46552', '21.45145', '21.43822', '21.42734', '21.41222', '21.40132', '21.37679']
>>> ints = [int(float(num)) for num in lst]
[21, 21, 21, 21, 21, 21, 21, 21]

Answer 3

foo = ['21.48678', '21.46552', '21.45145', '21.43822', '21.42734', '21.41222', '21.40132', '21.37679']

map(lambda x: int(float(x)), foo)

Answer 4

[int(round(float(i))) for i in example_list]

將列表中的項目轉換為float ，將其舍入 ，然后將其轉換為int 。

Answer 5

new_list=[]
for each in example_list:
    Integer = int(each)
    new_list.append(Integer)
print new_list

這對於初學者來說很容易理解：D