[英]SQL: How to filter to return only the rows from a result set where certain data in a field appears in more than one row of the unfiltered result set?
[英]How to return rows only if there is more than one result
在Oracle 10g數據庫中,我想構建一個SQL查詢,該查詢僅在有多個行結果時才返回結果行。
有可能嗎?
您需要計算返回結果的數量,如果您不希望分組,可以使用以下方法:
SELECT *
FROM (SELECT col1,
col2,
COUNT(*) OVER() cnt
FROM your_table
WHERE <conditions> )
WHERE cnt > 1
select * from
(select column1,column2,column3,
(select count(*) from table1 where '*XYZ Condition*' ) as rowCount
from table1 where '*XYZ Condition*')
where rowCount > 1;
您只需要在查詢的兩個位置都放置相同的條件,即,兩個where
子句的“ XYZ條件 ”都相同。
您是否需要以下結果?
c1 c2
1 AA
1 BB
2 CC
結果:
c1 c2
1 AA,BB
2 CC
以下內容可以滿足您的要求。
select c1,ltrim(sys_connect_by_path(c2,','),',') from (
select c1,c2, row_number() over(partition by c1 order by c2)rn,
count(*) over(partition by id ) cnt from XXX -- XXX: your table
) a where level=cnt
start with rn=1 connect by prior c1=c1 and prior rn=rn-1
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