如何查找兩個日期之間的天數

Question

我有一個基本的查詢：

SELECT dtCreated
    , bActive
    , dtLastPaymentAttempt
    , dtLastUpdated
    , dtLastVisit
FROM Customers
WHERE (bActive = 'true') 
    AND (dtLastUpdated > CONVERT(DATETIME, '2012-01-0100:00:00', 102))

我想在輸出中添加另一列...讓我們稱之為“差異”以找出'dtcreated'和'dtlastupdated'之間的天數所以例如如果記錄1的dtcreated為1/1/11並且dtlastupdated是1/1/12，“差異”列將是“365”。

這可以在查詢中完成嗎？

Answer 1

你會使用DATEDIFF ：

declare @start datetime
declare @end datetime

set @start = '2011-01-01'
set @end = '2012-01-01'

select DATEDIFF(d, @start, @end)

results = 365

所以對於您的查詢：

SELECT dtCreated
    , bActive
    , dtLastPaymentAttempt
    , dtLastUpdated
    , dtLastVisit
    , DATEDIFF(d, dtCreated, dtLastUpdated) as Difference
FROM Customers
WHERE (bActive = 'true') 
    AND (dtLastUpdated > CONVERT(DATETIME, '2012-01-0100:00:00', 102))

Answer 2

要查找兩個日期之間的天數，請使用：

DATEDIFF ( d, startdate , enddate )

Answer 3

我會使用DATE_DIFF函數來提供如下值：

SELECT dtCreated
    , bActive
    , dtLastPaymentAttempt
    , dtLastUpdated
    , dtLastVisit
    , DATEDIFF(d, dtLastUpdated, dtCreated) AS Difference
FROM Customers
WHERE (bActive = 'true') 
    AND (dtLastUpdated > CONVERT(DATETIME, '2012-01-0100:00:00', 102))

編輯：如果使用MySQL你省略了'd'離開你

DATEDIFF(dtLastUpdated, dtCreated) AS Difference

Answer 4

如果您使用MySQL，則有DATEDIFF函數計算兩個日期之間的天數：

SELECT dtCreated
    , bActive
    , dtLastPaymentAttempt
    , dtLastUpdated
    , dtLastVisit
    , DATEDIFF(dtLastUpdated, dtCreated) as Difference
FROM Customers
WHERE (bActive = 'true') 
    AND (dtLastUpdated > CONVERT(DATETIME, '2012-01-0100:00:00', 102))

Answer 5

DATEDIFF(d, 'Start Date', 'End Date')

做到這一點

Answer 6

DATEDIFF函數用於計算所需日期之間的天數

例如，如果您是字符串格式的給定日期的差異當前日期

SELECT * , DATEDIFF(CURDATE(),STR_TO_DATE('01/11/2017', '%m/%d/%Y')) AS days FROM consignments WHERE code = '1610000154'

這里， STR_TO_DATE （）：取一個字符串並返回格式掩碼指定的日期;

對於你的例子：

SELECT dtCreated
    , bActive
    , dtLastPaymentAttempt
    , dtLastUpdated
    , dtLastVisit
    , DATEDIFF(dtLastUpdated, dtCreated) as Difference
FROM Customers
WHERE (bActive = 'true') 
    AND (dtLastUpdated > '2012-01-01 00:00:00')

在mysql服務器5.7.17上測試

Answer 7

正如@Forte L.所提到的，你也可以做到以下幾點;

SELECT dtCreated
    , bActive
    , dtLastPaymentAttempt
    , dtLastUpdated
    , dtLastVisit

    , DATEDIFF(day, dtCreated, dtLastUpdated) Difference

FROM Customers
WHERE (bActive = 'true') 
    AND (dtLastUpdated > CONVERT(DATETIME, '2012-01-0100:00:00', 102))

Answer 8

DECLARE @Firstdate DATE='2016-04-01',
 @LastDate DATE=GETDATE(),/*get today date*/
 @resultDay int=null

SET @resultDay=(SELECT DATEDIFF(d, @Firstdate, @LastDate))
PRINT @resultDay

Answer 9

兩天之間獲得天數

DECLARE @date1 DATE='2015-01-01',
 @date2 DATE='2019-01-01',
 @Total int=null

SET @Total=(SELECT DATEDIFF(DAY, @date1, @date2))
PRINT @Total