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從每個組中選擇隨機值SQL

[英]Select random values from each group, SQL

我有一個項目,通過它我可以創建一個由數據庫驅動的游戲。

數據庫輸入的數據如下:

(身份證,姓名)|| (1,PhotoID),(1,PhotoID),(1,PhotoID),(2,PhotoID),(2,PhotoID)等。 有數以千計的條目。

這是我當前的SQL語句:

$sql = "SELECT TOP 8 * FROM Image WHERE Hidden = '0' ORDER BY NEWID()";

但是這也可以產生具有匹配ID的結果,其中我需要使每個結果具有唯一ID(即我需要來自每個組的一個結果)。

如何更改查詢以從每個組中獲取一個結果?

謝謝!

由於ORDER BY NEWID()無論如何都會導致表掃描,因此您可以使用row_number()來隔離組中的第一個:

; with randomizer as (
  select id,
         name,
         row_number() over (partition by id
                            order by newid()) rn
    from Image
   where hidden = 0
)
select top 8
       id,
       name
  from randomizer
 where rn = 1
-- Added by mellamokb's suggestion to allow groups to be randomized
order by newid()

由於mellamokb, Sql Fiddle游樂場

看起來這可能有用,但我無法保證性能:

SELECT TOP 8 ID,
  (select top 1 name from image i2
   where i2.id = i1.id order by newid())
FROM Image i1
WHERE hidden = '0'
group by ID
ORDER BY NEWID();

演示: http ://www.sqlfiddle.com/#!3 / 657ad / 6

如果您在ID列上有索引並希望利用索引並避免全表掃描,請首先對鍵值進行隨機化:

WITH IDs AS
(
  SELECT DISTINCT ID
  FROM Image
  WHERE Hidden = '0'
),
SequencedIDs AS
(
  SELECT ID, ROW_NUMBER() OVER (ORDER BY NEWID()) AS Seq
  FROM IDs
),
ImageGroups AS
(
  SELECT i.*, ROW_NUMBER() OVER (PARTITION BY i.ID ORDER BY NEWID()) Seq
  FROM SequencedIDs s
  INNER JOIN Image i
    ON i.ID = s.ID
  WHERE s.Seq < 8
  AND i.Hidden = '0'
)
SELECT *
FROM ImageGroups
WHERE Seq = 1

這應該大大降低了表掃描方法的成本,雖然我沒有足夠大的模式可以測試 - 所以嘗試在SSMS中運行一些統計信息並確保ID實際上被索引以使其有效。

select * from (select * from photos order by rand()) as _SUB group by _SUB.id;
 select ID, Name from (select ID, Name, row_number() over 
 (partition by ID, Name order by ID) as ranker from Image where Hidden = 0 ) Z where ranker = 1
 order by newID()

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