[英]ASP.NET MVC 4 EF5 with MySQL
所以我剛拿起VS2012,我想用EF5啟動一個ASP.NET MVC 4應用程序。
我的主機沒有MSSQL所以我必須使用MySQL。
如何告訴我的應用程序它應該使用MySQL? (我要么使用devart MySQL連接器,要么使用mysql.com中的連接器)
您需要使用連接字符串DbProviderFactory和MySql Connector 6.5.4的自定義DatabaseInitializer設置配置。 我詳細介紹了使用EF5和MySql的完整步驟,包括我博客上初始化程序的代碼 。 如果您需要ASP.Net成員資格提供程序解決方案之前曾被問過: ASP.NET的成員身份/角色提供程序? 我將在此處發布解決方案,以獲得完整的EF5 MySql解決方案。
MySql連接器當前不支持EF 5遷移,ASP.NET僅支持MS SQL上的SimpleMembership(默認為MVC4)而不支持MySql。 以下解決方案適用於Code First。
步驟是:
<system.data>
<DbProviderFactories>
<remove invariant="MySql.Data.MySqlClient"/>
<add name="MySQL Data Provider" invariant="MySql.Data.MySqlClient"
description=".Net Framework Data Provider for MySQL"
type="MySql.Data.MySqlClient.MySqlClientFactory,MySql.Data" />
</DbProviderFactories>
</system.data>
<connectionStrings>
<add name="ConnectionStringName"
connectionString="Datasource=hostname;Database=schema_name;uid=username;pwd=Pa$$w0rd;"
providerName="MySql.Data.MySqlClient" />
</connectionStrings>
如果您正在使用NuGet(6.5.4)中的MySql連接器,則需要自定義初始化程序。 代碼見http://brice-lambson.blogspot.se/2012/05/using-entity-framework-code-first-with.html或http://www.nsilverbullet.net/2012/11/07/ 6步對得到實體框架-5-勞動與MySQL的-5-5 /
然后將其添加到配置中
<configSections>
<section name="entityFramework"
type="System.Data.Entity.Internal.ConfigFile.EntityFrameworkSection,
EntityFramework, Version=5.0.0.0, Culture=neutral,
PublicKeyToken=b77a5c561934e089" />
</configSections>
<entityFramework>
<contexts>
<context type="Namespace.YourContextName, AssemblyName">
<databaseInitializer
type="Namespace.YourChosenInitializer, AssemblyName">
</databaseInitializer>
</context>
</contexts>
<defaultConnectionFactory
type="MySql.Data.MySqlClient.MySqlClientFactory,MySql.Data" />
</entityFramework>
<membership defaultProvider="MySqlMembershipProvider">
<providers>
<clear />
<add name="MySqlMembershipProvider"
type="MySql.Web.Security.MySQLMembershipProvider,
MySql.Web, Version=6.5.4.0, PublicKeyToken=c5687fc88969c44d"
autogenerateschema="true"
connectionStringName="*NAME_OF_YOUR_CONN_STRING*"
enablePasswordRetrieval="false"
enablePasswordReset="true"
requiresQuestionAndAnswer="false"
requiresUniqueEmail="false"
passwordFormat="Hashed"
maxInvalidPasswordAttempts="5"
minRequiredPasswordLength="6"
minRequiredNonalphanumericCharacters="0"
passwordAttemptWindow="10"
passwordStrengthRegularExpression=""
applicationName="/" />
</providers>
</membership>
獲取AccountController和Views工作:
@Html.Partial(“_LoginPartial”)
替換共享_Layout視圖中的@Html.Partial(“_LogOnPartial”)
<add name="ConnectionString" providerName="MySql.Data.MySqlClient" connectionString="Data Source=127.0.0.1; port=3306; Initial Catalog=DbName; uid=root; pwd=*Password*;" />
安裝包:
PM> Install-Package EntityFramework
PM> Update-Package EntityFramework
PM> Install-Package MySql.Data.Entity
Web.config文件
<connectionStrings>
<add name="DefaultConnection"
providerName="MySql.Data.MySqlClient"
connectionString="Data Source=localhost;port=3306;Initial Catalog=api_db;User Id=root;password=''"/>
</connectionStrings>
創建模型類
using System;
using System.Collections.Generic;
using System.ComponentModel.DataAnnotations;
using System.ComponentModel.DataAnnotations.Schema;
using System.Linq;
using System.Web;
namespace LiteRemit.Models
{
[Table("customers")]
public class CustomerModel
{
[Key]
public int CustomerId { get; set; }
public string Name { get; set; }
public string Country { get; set; }
}
}
創建模型上下文:
using System;
using System.Collections.Generic;
using System.Data.Entity;
using System.Linq;
using System.Web;
namespace LiteRemit.Models
{
public class MySqlCon : DbContext
{
//MySql Database connection String
public MySqlCon() : base(nameOrConnectionString: "DefaultConnection") { }
public virtual DbSet<CustomerModel> Customers { get; set; }
}
}
創建控制器類
using LiteRemit.Models;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
namespace LiteRemit.Controllers
{
public class HomeController : Controller
{
MySqlCon _con;
public HomeController()
{
_con = new MySqlCon();
}
public ActionResult Index()
{
return View(_con.Customers.ToList());
}
}
}
代碼添加視圖頁面:
@using LiteRemit.Models
@model IEnumerable<CustomerModel>
<table border="1">
@foreach (var item in Model)
{
<tr>
<td>@Html.DisplayFor(modelItem => item.CustomerId)</td>
<td>
@Html.DisplayFor(modelItem => item.Name)
</td>
<td>@Html.DisplayFor(modelItem => item.Country)</td>
</tr>
}
</table>
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.