如何將數據插入到 SQL Server

Question

我的編碼有什么問題？ 我無法將數據插入 ms sql .. 我使用 C# 作為前端，使用 MS SQL 作為數據庫......

name = tbName.Text;
userId = tbStaffId.Text;
idDepart = int.Parse(cbDepart.SelectedValue.ToString());

string saveStaff = "INSERT into tbl_staff (staffName,userID,idDepartment) " +
                   " VALUES ('" + name + "', '" + userId +"', '" + idDepart + "');";

SqlCommand querySaveStaff = new SqlCommand(saveStaff);

try
{
querySaveStaff.ExecuteNonQuery();
}
catch
{
//Error when save data

MessageBox.Show("Error to save on database");
openCon.Close();
Cursor = Cursors.Arrow;
}

Answer 1

您必須設置 Command 對象的 Connection 屬性並使用參數化查詢而不是硬編碼 SQL 來避免SQL Injection 。

 using(SqlConnection openCon=new SqlConnection("your_connection_String"))
    {
      string saveStaff = "INSERT into tbl_staff (staffName,userID,idDepartment) VALUES (@staffName,@userID,@idDepartment)";

      using(SqlCommand querySaveStaff = new SqlCommand(saveStaff))
       {
         querySaveStaff.Connection=openCon;
         querySaveStaff.Parameters.Add("@staffName",SqlDbType.VarChar,30).Value=name;
         .....
         openCon.Open();

         querySaveStaff.ExecuteNonQuery();
       }
     }

Answer 2

我認為您缺乏將Connection對象傳遞給您的command對象。 如果您為此使用command和parameters ，那就更好了。

using (SqlConnection connection = new SqlConnection("ConnectionStringHere"))
{
    using (SqlCommand command = new SqlCommand())
    {
        command.Connection = connection;            // <== lacking
        command.CommandType = CommandType.Text;
        command.CommandText = "INSERT into tbl_staff (staffName, userID, idDepartment) VALUES (@staffName, @userID, @idDepart)";
        command.Parameters.AddWithValue("@staffName", name);
        command.Parameters.AddWithValue("@userID", userId);
        command.Parameters.AddWithValue("@idDepart", idDepart);

        try
        {
            connection.Open();
            int recordsAffected = command.ExecuteNonQuery();
        }
        catch(SqlException)
        {
            // error here
        }
        finally
        {
            connection.Close();
        }
    }
}

Answer 3

string saveStaff = "INSERT into student (stud_id,stud_name) " + " VALUES ('" + SI+ "', '" + SN + "');";
cmd = new SqlCommand(saveStaff,con);
cmd.ExecuteNonQuery();