ORACLE SQL 獲取從 2 個選擇語句中檢索的兩個值的差異

Question

我們有 2 個非常簡單的 SELECT 語句：

SELECT value from table where date between DATE1 and DATE2
SELECT value from table where date between DATE3 and DATE4

我們需要一種編寫單個 SQL 語句的方法，該語句將獲取從這兩個 SQL 語句返回的“值”的差異。

我們嘗試了以下方法，但沒有成功：

SELECT value from table where date between DATE1 and DATE2
minus 
SELECT value from table where date between DATE3 and DATE4

任何建議都受到高度贊賞。

Answer 1

未經測試但應該可以工作：

SELECT
    (SELECT value from table where date between DATE1 and DATE2) - 
    (SELECT value from table where date between DATE3 and DATE4)
FROM dual;

假設您的SELECT value保證返回單個值

Answer 2

SELECT value FROM TBL WHERE date BETWEEN DATE1 and DATE2 
AND value NOT IN (SELECT value FROM TBL WHERE date BETWEEN DATE3 AND DATE4)

Answer 3

如果您認為您的內部查詢可以提供多個值，請在下面使用

SELECT
    (SELECT sum(value) from table where date between DATE1 and DATE2) - 
    (SELECT sum(value) from table where date between DATE3 and DATE4) as answer
FROM dual;

Answer 4

請試試這個：

SET SERVEROUTPUT ON
DECLARE
V_FIRST NUMBER := 0;
V_SECOND NUMBER := 0;
BEGIN
  SELECT value into V_FIRST from table where rownum=1 and date between DATE1 and DATE2;
  SELECT value into V_SECOND from table where rownum=1 and date between DATE3 and DATE4;

  DBMS_OUTPUT.PUT_LINE (V_FIRST-V_SECOND); 
END;

Answer 5

(
SELECT value from table where date between DATE1 and DATE2
 minus 
SELECT value from table where date between DATE3 and DATE4
)
union all
(
SELECT value from table where date between DATE3 and DATE4
 minus 
SELECT value from table where date between DATE1 and DATE2
)

Answer 6

以下聲明應該適用於您的情況

(
SELECT value from table where date between DATE3 and DATE4
 minus 
SELECT value from table where date between DATE1 and DATE2
)
union
(
SELECT value from table where date between DATE1 and DATE2
 minus 
SELECT value from table where date between DATE3 and DATE4
)