正數表示0到12之間的正數

Question

我試過沒有運氣搜索互聯網上的正則表達式，檢查：

• 積極的＃
• 在0到12之間

我需要將它放在這個特定代碼行的括號中

 Regex rxValidHeightInches = new Regex();

任何幫助將不勝感激！

謝謝

Answer 1

這應該工作^(\\d|(1[0-2]))$

var rxValidHeightInches = new Regex("^(\\d|(1[0-2]))$");

Answer 2

試試這個吧。

(?<!-)(\b((1[01])|[1-9])\b)

它匹配1 - 9或10或11 。 始終排除負數。

釋

-Assert that it is impossible to match the regex below with the match ending at this position (negative lookbehind) «(?<!-)»
---Match the character “-” literally «-»
-Match the regular expression below and capture its match into backreference number 1 «(\b((1[01])|[1-9])\b)»
---Assert position at a word boundary «\b»
---Match the regular expression below and capture its match into backreference number 2 «((1[01])|[1-9])»
------Match either the regular expression below (attempting the next alternative only if this one fails) «(1[01])»
---------Match the regular expression below and capture its match into backreference number 3 «(1[01])»
------------Match the character “1” literally «1»
------------Match a single character present in the list “01” «[01]»
------Or match regular expression number 2 below (the entire group fails if this one fails to match) «[1-9]»
---------Match a single character in the range between “1” and “9” «[1-9]»
---Assert position at a word boundary «\b»

屏幕截圖

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這一個包括0 - 12

(?<!-)(\b((1[0-2])|[0-9])\b)