[英]Async HTTPWebrequest with Timeout
環境:Windows CE / .NET Compact FrameWork 3.5。
我需要一些指導
1) 為異步 Web 請求實現超時功能。 ThreadPool::RegisterWaitForSingleObject() 不適用於 .NetCf,我有點卡住了。
2)如何判斷網絡本身是否不可用? 谷歌搜索沒有幫助。
注意:ThreadPool::RegisterWaitForSingleObject 不適用於 .NET Compact FrameWork。
這是我的異步實現:
void StartRequest ()
{
try
{
HttpWebRequest myHttpWebRequest = (HttpWebRequest)WebRequest.Create("http://192.78.221.11/SomeFunc/excpopulatedept");
RqstState myRequestState = new RqstState();
myRequestState.request = myHttpWebRequest;
// Start the asynchronous request.
IAsyncResult result =
(IAsyncResult)myHttpWebRequest.BeginGetResponse(new AsyncCallback(RespCallback), myRequestState);
// Release the HttpWebResponse resource.
myRequestState.response.Close();
}
catch (WebException ex)
{
;
}
catch (Exception ex)
{
;
}
}
private void RespCallback(IAsyncResult asynchronousResult)
{
try
{
//State of request is asynchronous.
RqstState myRequestState = (RqstState)asynchronousResult.AsyncState;
HttpWebRequest myHttpWebRequest = myRequestState.request;
myRequestState.response = (HttpWebResponse)myHttpWebRequest.EndGetResponse(asynchronousResult);
// Read the response into a Stream object.
Stream responseStream = myRequestState.response.GetResponseStream();
myRequestState.streamResponse = responseStream;
// Begin the Reading of the contents of the HTML page and print it to the console.
IAsyncResult asynchronousInputRead = responseStream.BeginRead(myRequestState.BufferRead, 0, 1024, new AsyncCallback(ReadCallBack), myRequestState);
return;
}
catch (WebException e)
{
Console.WriteLine("\nRespCallback Exception raised!");
Console.WriteLine("\nMessage:{0}", e.Message);
Console.WriteLine("\nStatus:{0}", e.Status);
}
}
private void ReadCallBack(IAsyncResult asyncResult)
{
try
{
RqstState myRequestState = (RqstState)asyncResult.AsyncState;
Stream responseStream = myRequestState.streamResponse;
int read = responseStream.EndRead(asyncResult);
// Read the HTML page and then print it to the console.
if (read > 0)
{
myRequestState.requestData.Append(Encoding.ASCII.GetString(myRequestState.BufferRead, 0, read));
IAsyncResult asynchronousResult = responseStream.BeginRead(myRequestState.BufferRead, 0, 1024, new AsyncCallback(ReadCallBack), myRequestState);
return;
}
else
{
//Console.WriteLine("\nThe contents of the Html page are : ");
if (myRequestState.requestData.Length > 1)
{
string stringContent;
stringContent = myRequestState.requestData.ToString();
responseStream.Close();
}
catch (WebException e)
{
}
}
}
}
感謝您的時間。
要繼續 Eric J 的評論,您在捕獲之前有myRequestState.response.Close()
。 這幾乎總是會拋出異常,因為要么response
為空,要么response
不會被打開。 這是因為您正在異步調用BeginGetResponse
並且您給它的回調可能不會在調用下一行 (response.close) 時被調用。 你會想要解決這個問題,而不是僅僅隱藏異常,因為你不知道它們為什么會發生。
就超時而言,因為您正在處理的事情本身沒有可配置的超時,所以您必須設置一個計時器並在超時結束時簡單地關閉連接。 例如
HttpWebRequest myHttpWebRequest; // ADDED
Timer timer; // ADDED
private void StartRequest()
{
myHttpWebRequest = (HttpWebRequest)WebRequest.Create("http://192.78.221.11/SomeFunc/excpopulatedept");
RqstState myRequestState = new RqstState();
myRequestState.request = myHttpWebRequest;
timer = new Timer(delegate { if (!completed) myHttpWebRequest.Abort(); }, null, waitTime, Timeout.Infinite); // ADDED
// Start the asynchronous request.
IAsyncResult result =
(IAsyncResult)myHttpWebRequest.BeginGetResponse(new AsyncCallback(RespCallback), myRequestState);
}
//...
private void ReadCallBack(IAsyncResult asyncResult)
{
try
{
RqstState myRequestState = (RqstState)asyncResult.AsyncState;
Stream responseStream = myRequestState.streamResponse;
int read = responseStream.EndRead(asyncResult);
// Read the HTML page and then print it to the console.
if (read > 0)
{
myRequestState.requestData.Append(Encoding.ASCII.GetString(myRequestState.BufferRead, 0, read));
IAsyncResult asynchronousResult = responseStream.BeginRead(myRequestState.BufferRead, 0, 1024, new AsyncCallback(ReadCallBack), myRequestState);
}
else
{
completed = true; // ADDED
using(timer) // ADDED
{
timer = null;
}
if (myRequestState.requestData.Length > 1)
{
string stringContent;
stringContent = myRequestState.requestData.ToString();
responseStream.Close();
}
}
}
}
我只復制並粘貼了您的代碼,因此編譯的可能性與您最初提供的代碼一樣,但是應該有足夠的內容讓您朝着正確的方向前進。
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