[英]Python: How can I calculate the average word length in a sentence using the .split command?
這里是 python 的新手。 我正在嘗試編寫一個計算句子中平均單詞長度的程序,我必須使用 .split 命令來完成。 順便說一句,我使用 python 3.2
這是我到目前為止寫的
sentence = input("Please enter a sentence: ")
print(sentence.split())
到目前為止,我讓用戶輸入了一個句子,它成功地拆分了他們輸入的每個單詞,例如:嗨,我的名字是 Bob,它將它拆分為 ['hi', 'my', 'name', 'is', '鮑勃']
但現在我迷路了,我不知道如何讓它計算每個單詞並找到句子的平均長度。
在 Python 3(您似乎正在使用)中:
>>> sentence = "Hi my name is Bob"
>>> words = sentence.split()
>>> average = sum(len(word) for word in words) / len(words)
>>> average
2.6
您可能想要過濾掉標點符號以及零長度的單詞。
>>> sentence = input("Please enter a sentence: ")
過濾掉不重要的標點符號。 如果需要,您可以在標點字符串中添加更多內容:
>>> filtered = ''.join(filter(lambda x: x not in '".,;!-', sentence))
拆分成單詞,並刪除長度為零的單詞:
>>> words = [word for word in filtered.split() if word]
並計算:
>>> avg = sum(map(len, words))/len(words)
>>> print(avg)
3.923076923076923
>>> sentence = "Hi my name is Bob"
>>> words = sentence.split()
>>> sum(map(len, words))/len(words)
2.6
簡潔版:
average = lambda lst: sum(lst)/len(lst) #average = sum of numbers in list / count of numbers in list
avg = average([len(word) for word in sentence.split()]) #generate a list of lengths of words, and calculate average
分步版本:
def average(numbers):
return sum(numbers)/len(numbers)
sentence = input("Please enter a sentence: ")
words = sentence.split()
lengths = [len(word) for word in words]
print 'Average length:', average(lengths)
輸出:
>>>
Please enter a sentence: Hey, what's up?
Average length: 4
def main():
sentence = input('Enter the sentence: ')
SumAccum = 0
for ch in sentence.split():
character = len(ch)
SumAccum = SumAccum + character
average = (SumAccum) / (len(sentence.split()))
print(average)
def averageWordLength(mystring):
tempcount = 0
count = 1
wordcount = 0
try:
for character in mystring:
if character == " ":
tempcount +=1
if tempcount ==1:
count +=1
else:
tempcount = 0
try:
if character.isalpha(): #sorry for using the .isalpha
wordcount += 1
except:
wordcount = wordcount + 0
if mystring[0] == " " or mystring.endswith(" "): #i'm sorry for using the .endswith
count -=1
try:
result = wordcount/count
if result == 0:
result = "No words"
return result
else:
return result
except ZeroDivisionError:
error = "No words"
return error
except Exception:
error = "Not a string"
return error
mystring = "你有多大的空間!" 輸出為 3.0,我沒有使用拆分
作為模塊化:
import re
def avg_word_len(s):
words = s.split(' ') # presuming words split by ' '. be watchful about '.' and '?' below
words = [re.sub(r'[^\w\s]','',w) for w in words] # re sub '[^\w\s]' to remove punctuations first
return sum(len(w) for w in words)/float(len(words)) # then calculate the avg, dont forget to render answer as a float
if __name__ == "__main__":
s = raw_input("Enter a sentence")
print avg_word_len(s)
s = input("Please enter a sentence: ")
avg_word_len = len(s.replace(' ',''))/len(s.split())
print('Word average =', avg_word_len)
輸出:
Please enter a sentence: this is a testing string
Word average = 4.0
注意:這是一個普通的用例,可以根據需要應用額外的邊界條件。
text = input()
words=text.split()
single=''.join(words)
average=len(single)/len(words)
print(average)
def average():
value = input("Enter the sentence:")
sum = 0
storage = 0
average = 0
for i in range (len(value)):
sum = sum + 1
storage = sum
average = average+storage
print (f"the average is :{average/len(value)}")
return average/len(value)
average()
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