從HTTP Post接收XML

Question

所以我有以下代碼：

    public void SendToApplication(HttpServletRequest request) throws IOException, TransformerException {

        BufferedReader br = new BufferedReader(new FileReader(new File("CreatePoll.xml")));
        String line;
        StringBuilder sb = new StringBuilder();

        while((line=br.readLine())!= null) sb.append(line.trim());

        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost postRequest = new HttpPost("http://localhost:8080/cs9322.simple.rest.doodle/rest/polls/comment");
        StringEntity input = new StringEntity(sb.toString());
        input.setContentType("text/xml");
        postRequest.setEntity(input);
        HttpResponse response = httpClient.execute(postRequest);
        HttpEntity entity = response.getEntity();

    }

讀取XML文件（CreatePoll.xml），

<Comment xmlns:xs="http://localhost:8080/cs9322.simple.rest.doodle/CommentSchema">
  <Poll_ID>2</Poll_ID>
  <Name>Bob</Name>
  <Text>testing junk</Text>
  <Timestamp>2012-10-14T12:37:04</Timestamp>
</Comment>

並將其發布到Web服務，我現在遇到的問題是嘗試在發送后從Web服務接收XML響應。 我打算接收的XML是：

<comment>
    <address>
    </address>
</comment>

有人可以在這里幫助我，不勝感激！

Answer 1

如果您使用Apache Commons IO ，則可以使用IOUtils類從HttpEntity讀取輸入流。 使用twitter rest API的示例：

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost("http://search.twitter.com/search.atom?q=elkstein&count=5");
HttpResponse response = httpClient.execute(postRequest);

HttpEntity entity = response.getEntity();
String body = IOUtils.toString(entity.getContent(), "UTF-8");