[英]create a statistics table using datetime MSSQL Query
我的桌子很少,給我帶來了很大的困難:
Person datetime1 datetime2
Eric 2012-10-01 09:00:05.000 2012-10-01 22:00:00.000
Anna 2012-10-02 06:00:05.000 2012-10-03 12:00:05.000
Richard 2012-10-03 09:00:05.000 2012-10-04 02:00:05.000
Chuck 2012-10-01 12:00:05.000 2012-10-01 23:00:05.000
我正在嘗試編寫查詢,該查詢為我提供了統計表。 下表包含有關用戶何時登錄和注銷的信息(每日粒度):
Date logged_in logged_off
2012-10-01 2 2
2012-10-02 1 0
2012-10-03 1 1
2012-10-04 0 1
根據我的研究,樞軸命令可以解決問題嗎?
select Person,
SUM(case when datetime1 = '2012-10-01' then 1 else 0 end) as [loggeed_in],
SUM(case when datetime2 = '2012-10-01' then 1 else 0 end) as [logged_of]
from table
group by Person
這行不通...您有任何想法嗎?
這將解決當前查詢,但是不知道是否可以解決整個問題...
select Person,
SUM(case when convert(varchar(10), datetime1, 111) = '2012/10/01' then 1 else 0 end) as [loggeed_in],
SUM(case when convert(varchar(10), datetime2, 111) = '2012/10/01' then 1 else 0 end) as [logged_of]
from table
group by Person
編輯:我相信這將更適合需求...
SELECT
[Date] = dt,
logged_in = (
SELECT COUNT(*)
FROM table1
WHERE convert(varchar(10), datetime1, 111) = convert(varchar(10), dt, 111)),
logged_off = (
SELECT COUNT(*)
FROM table1
WHERE convert(varchar(10), datetime2, 111) = convert(varchar(10), dt, 111))
FROM (
SELECT TOP 1000
row_number() OVER(ORDER BY (SELECT 0)) AS N
FROM master.dbo.syscolumns sc1, master.dbo.syscolumns sc2) tally
CROSS APPLY(
SELECT dt = DATEADD(dd, tally.N - 1, '2012-10-1')) tallydt
WHERE dt BETWEEN (SELECT MIN(dateadd(dd, -1, datetime1)) FROM table1) AND (SELECT MAX(datetime2) FROM table1)
GROUP BY dt
ORDER BY dt
這是有效的解決方案:
WITH O AS (
SELECT
CAST([login Date & Time] AS DATE) loginDate
,COUNT(*) logined
FROM table
GROUP BY CAST([login Date & Time] AS DATE)
), C AS (
SELECT
CAST([Close Date & Time] AS DATE) CloseDate
,COUNT(*) Closed
FROM table
WHERE [Close Date & Time] IS NOT NULL
GROUP BY CAST([Close Date & Time] AS DATE)
)
SELECT
COALESCE(C.CloseDate, O.loginDate) TheDate
--,O.loginDate
--,C.CloseDate
,O.logined
,C.Closed
FROM O
FULL JOIN C
ON O.loginDate = C.CloseDate
ORDER BY TheDate
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