排序字典並更改索引

Question

在我的應用程序中，我有一個包含兩個數組的字典，例如：

NSDictionary *d=[[NSDictionary alloc]initWithObjectsAndKeys:listOfEvents,@"l",arr_distance,@"d", nil];
        NSLog(@"%@",d);


 d =     (
    "353.90",
    "354.68",
    "350.42",
    "1.18"
);
l =     (
            {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           },
         {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           },
      {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           },
      {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           }
); 
}

我想用第一個數組對字典進行排序，當索引更改時，第二個數組索引也根據它而更改。

兩個數組的索引彼此相關。

@ABC您嘗試過的代碼

NSDictionary *dict = [NSDictionary dictionaryWithObjects:listOfEvents  forKeys:arr_distance];
        NSArray *sortedArray = [arr_distance sortedArrayUsingSelector:@selector(compare:)];
        NSMutableArray *sortedValues = [NSMutableArray array];

    for (NSString *key in sortedArray) {
        [sortedValues addObject:[dict valueForKey:key]];
    }

    NSLog(@"%@",sortedValues);

結果：

{1.18,2563.91,2563.41,2563.39,350,353,354}

Answer 1

這是一種方法，

    NSArray *a = [NSArray arrayWithObjects:@"8", @"2", @"4", nil];
    NSArray *b = [NSArray arrayWithObjects:@"val1", @"val2", @"val3", nil];//This can be an array of any objects

要么

a = ["353.90", "354.68", "350.42", "1.18"];
b = [{
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           },
         {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           },
      {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
           },
      {
        Contestant1 = "Jon jones";
        Contestant2 = "Anderson silva";
       }];

像這樣做，

    NSDictionary *dict = [NSDictionary dictionaryWithObjects:b forKeys:a];
    NSArray *sortedArray = [a sortedArrayUsingComparator:^(id firstObject, id secondObject) {
        return [((NSString *)firstObject) compare:((NSString *)secondObject) options:NSNumericSearch];
    }];
    NSMutableArray *sortedValues = [NSMutableArray array];

    for (NSString *key in sortedArray) {
        [sortedValues addObject:[dict valueForKey:key]];
    }

    NSLog(@"%@",sortedValues);