[英]Check if List<Int32> values are consecutive
List<Int32> dansConList = new List<Int32>();
dansConList[0] = 1;
dansConList[1] = 2;
dansConList[2] = 3;
List<Int32> dansRandomList = new List<Int32>();
dansRandomList[0] = 1;
dansRandomList[1] = 2;
dansRandomList[2] = 4;
我需要一種方法,在評價上述列表時,會返回false
的dansRandomList
和true
的dansConList
基於這樣的事實dansConList
在它的值連續數列,並dansRandomList沒有(缺值3)。
如果可能,最好使用 LINQ。
我試過的:
單行,只迭代到第一個不連續的元素:
bool isConsecutive = !myIntList.Select((i,j) => i-j).Distinct().Skip(1).Any();
更新:這是如何工作的幾個例子:
Input is { 5, 6, 7, 8 }
Select yields { (5-0=)5, (6-1=)5, (7-2=)5, (8-3=)5 }
Distinct yields { 5, (5 not distinct, 5 not distinct, 5 not distinct) }
Skip yields { (5 skipped, nothing left) }
Any returns false
Input is { 1, 2, 6, 7 }
Select yields { (1-0=)1, (2-1=)1, (6-2=)4, (7-3=)4 } *
Distinct yields { 1, (1 not distinct,) 4, (4 not distinct) } *
Skip yields { (1 skipped,) 4 }
Any returns true
* Select 不會產生第二個 4 並且 Distinct 不會檢查它,因為 Any 將在找到第一個 4 后停止。
var min = list.Min();
var max = list.Max();
var all = Enumerable.Range(min, max - min + 1);
return list.SequenceEqual(all);
var result = list
.Zip(list.Skip(1), (l, r) => l + 1 == r)
.All(t => t);
您可以使用此擴展方法:
public static bool IsConsecutive(this IEnumerable<int> ints )
{
//if (!ints.Any())
// return true; //Is empty consecutive?
// I think I prefer exception for empty list but I guess it depends
int start = ints.First();
return !ints.Where((x, i) => x != i+start).Any();
}
像這樣使用它:
[Test]
public void ConsecutiveTest()
{
var ints = new List<int> {1, 2, 4};
bool isConsecutive = ints.IsConsecutive();
}
擴展方法:
public static bool IsConsecutive(this IEnumerable<int> myList)
{
return myList.SequenceEqual(Enumerable.Range(myList.First(), myList.Last()));
}
用途:
bool isConsecutive = dansRandomList.IsConsecutive();
這是另一個。 它同時支持 {1,2,3,4} 和 {4,3,2,1}。 它測試序列號差異是否等於 1 或 -1。
Function IsConsecutive(ints As IEnumerable(Of Integer)) As Boolean
If ints.Count > 1 Then
Return Enumerable.Range(0, ints.Count - 1).
All(Function(r) ints(r) + 1 = ints(r + 1) OrElse ints(r) - 1 = ints(r + 1))
End If
Return False
End Function
警告:如果為空,則返回 true。
var list = new int[] {-1,0,1,2,3};
var isConsecutive = list.Select((n,index) => n == index+list.ElementAt(0)).All (n => n);
為了檢查系列是否包含連續數字,您可以使用它
樣本
isRepeatable(121878999, 2);
結果 = 真
由於 9 重復了兩次,其中 upto 是連續次數
isRepeatable(37302293, 3)
結果 = 錯誤
因為沒有數字連續重復 3 次
static bool isRepeatable(int num1 ,int upto)
{
List<int> myNo = new List<int>();
int previous =0;
int series = 0;
bool doesMatch = false;
var intList = num1.ToString().Select(x => Convert.ToInt32(x.ToString())).ToList();
for (int i = 0; i < intList.Count; i++)
{
if (myNo.Count==0)
{
myNo.Add(intList[i]);
previous = intList[i];
series += 1;
}
else
{
if (intList[i]==previous)
{
series += 1;
if (series==upto)
{
doesMatch = true;
break;
}
}
else
{
myNo = new List<int>();
previous = 0;
series = 0;
}
}
}
return doesMatch;
}
// 1 | 2 | 3 | 4 | _
// _ | 1 | 2 | 3 | 4
// | 1 | 1 | 1 | => must be 1 (or 2 for even/odd consecutive integers)
var numbers = new List<int>() { 1, 2, 3, 4, 5 };
const step = 1; // change to 2 for even and odd consecutive integers
var isConsecutive = numbers.Skip(1)
.Zip(numbers.SkipLast(1))
.Select(n => {
var diff = n.First - n.Second;
return (IsValid: diff == step, diff);
})
.Where(diff => diff.IsValid)
.Distinct()
.Count() == 1;
或者我們可以寫得更短但可讀性較差:
var isConsecutive = numbers.Skip(1)
.Zip(numbers.SkipLast(1), (l, r) => (IsValid: (l-r == step), l-r))
.Where(diff => diff.IsValid)
.Distinct()
.Count() == 1;
老問題,但這是使用一些簡單代數的簡單方法。
不過,這只適用於您的整數從 1 開始的情況。
public bool AreIntegersConsecutive(List<int> integers)
{
var sum = integers.Sum();
var count = integers.Count();
var expectedSum = (count * (count + 1)) / 2;
return expectedSum == sum;
}
它僅適用於唯一列表。
List<Int32> dansConList = new List<Int32>();
dansConList.Add(7);
dansConList.Add(8);
dansConList.Add(9);
bool b = (dansConList.Min() + dansConList.Max())*((decimal)dansConList.Count())/2.0m == dansConList.Sum();
這是一個使用Aggregate
函數的擴展方法。
public static bool IsConsecutive(this List<Int32> value){
return value.OrderByDescending(c => c)
.Select(c => c.ToString())
.Aggregate((current, item) =>
(item.ToInt() - current.ToInt() == -1) ? item : ""
)
.Any();
}
用法:
var consecutive = new List<Int32>(){1,2,3,4}.IsConsecutive(); //true
var unorderedConsecutive = new List<Int32>(){1,4,3,2}.IsConsecutive(); //true
var notConsecutive = new List<Int32>(){1,5,3,4}.IsConsecutive(); //false
這是一個C版本的代碼,我認為根據邏輯用其他語言重寫它很容易。
int isConsecutive(int *array, int length) {
int i = 1;
for (; i < length; i++) {
if (array[i] != array[i - 1] + 1)
return 0; //which means false and it's not a consecutive list
}
return 1;
}
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