透視查詢 - SQL Server 2005

Question

我在 SQL Server 2005 中有以下查詢，它獲取下面提到的結果。

select Distinct(date),id,
           sum(convert(float,Gross)),
           count(*) as no from Daily
    group by date,id 
    order by date desc

Date                     id          Gross          Count
2012-11-25 00:00:00.000  Client id1  1232.6140752   12
2012-11-25 00:00:00.000  Client id2  1183.75621528  88
2012-11-26 00:00:00.000  Client id3  4561.459086    67
2012-11-26 00:00:00.000  Client id4  6781.15660608  440

現在我如何獲得以下格式的結果。 這看起來像是需要一個數據透視查詢，請幫忙

id           Date1  Date2  Date3  Date4  Date5 Date6 Date7
Client id1   Gross       
Client id2   Gross
Client id3   Gross

Answer 1

有兩種方法可以PIVOT ，一種是靜態版本，您對所有日期值進行硬編碼，另一種是動態版本，它將在運行時生成日期列表。

靜態版本：

如果您的日期數量有限，您的查詢將與此類似。

select id, [yourDate1], [yourDate2], [yourDate3]
from
(
  select date, id, cast(gross as float) as gross
  from Daily
) src
pivot
(
  sum(gross)
  for date in ([yourDate1], [yourDate2], [yourDate3])
) piv;

參見SQL Fiddle with Demo

動態版本：

此版本生成動態 SQL 以在運行時獲取日期列表。 您的代碼將類似於：

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT distinct ',' + QUOTENAME(date) 
                    from Daily
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT id, ' + @cols + ' from 
             (
               select date, id, cast(gross as float) as gross
               from Daily
            ) src
            pivot 
            (
                sum(gross)
                for date in (' + @cols + ')
            ) p '

execute(@query)

參見SQL Fiddle with Demo

Answer 2

WITH a AS
(
    SELECT [Id], [Gross]
    , [DateRank] = DENSE_RANK() OVER (ORDER BY [Date])
    FROM [Daily]
)
SELECT *
FROM a PIVOT
(
    SUM([Gross])
    FOR [DateRank] IN ([1], [2], [3], [4], [5], [6], [7])
) b