[英]How to convert a dictionary of tuples into a dictionary of lists (Python)?
我是Python的新手(並且是一般編程人員),但是我有一個字典,鍵為元組,並且我想用與列表相同的鍵創建一個新的字典。
這是我的意思:
我有:
d = {("apple", "banana", "pear", "pineapple"):24,
("banana", "pineapple", "apple", "pear"):17,
("pineapple", "pear", "banana", "apple"):10,
("apple", "pineapple", "banana", "pear"):16}
我想要:
new_d = {["apple", "banana", "pear", "pineapple"]:24,
["banana", "pineapple", "apple", "pear"]:17,
["pineapple", "pear", "banana", "apple"]:10,
["apple", "pineapple", "banana", "pear"]:16}
有沒有一種簡單的方法使用for循環和if語句來做到這一點?
列表不可散列,因此不能是字典中的鍵。
為什么要讓您的鑰匙成為清單? 如果您當前正在調用一個函數
expect_iterable_of_lists(d.keys())
,您只需將map
和list
組合即可:
expect_iterable_of_lists(map(list, d.keys()))
正如其他人所指出的那樣,將列表用作字典鍵可能不是一個好主意。
如果這是您真正需要的,則不難在列表中添加哈希值:
>>> class List(list):
def __hash__(self):
return hash(tuple(self))
>>> d = {("apple", "banana", "pear", "pineapple"):24,
("banana", "pineapple", "apple", "pear"):17,
("pineapple", "pear", "banana", "apple"):10,
("apple", "pineapple", "banana", "pear"):16}
>>> new_d = {List(k):v for k, v in d.items()}
>>> new_d
{['banana', 'pineapple', 'apple', 'pear']: 17,
['apple', 'banana', 'pear', 'pineapple']: 24,
['pineapple', 'pear', 'banana', 'apple']: 10,
['apple', 'pineapple', 'banana', 'pear']: 16}
該代碼將實現您使用列表鍵的目標,並且只要您不對列表進行突變(基於哈希表的指令不適用於可變鍵),它就可以正常工作。 如果確實需要更改鍵,則需要一個不依賴散列的替代字典實現(例如, 關聯列表 )。
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