JSON響應來自定義響應內容

Question

我已經實現了Spring MVC 3代碼來獲取JSON響應（借助Jackson映射器）

@RequestMapping(value = "/getallroles", method = RequestMethod.GET)
@ResponseBody
public JsonJtableResponse1 getAllRoles(){
    List<Role> roleList = testService.getAllRoles();
    JsonJtableResponse1 jstr = new JsonJtableResponse1("OK",roleList);
    return jstr;
}

JSON響應對象就是這樣。

public class JsonJtableResponse1 {

    private String Result;

    private List<Role> Records;

    public JsonJtableResponse1(String Result) {
        this.Result = Result;
    }

    public JsonJtableResponse1(List<Role> Records) {
        this.Records = Records;
    }

    public JsonJtableResponse1(String Result, List<Role> Records) {
        this.Result = Result;
        this.Records = Records;
    }

    public String getResult() {
        return Result;
    }

    public void setResult(String Result) {
        this.Result = Result;
    }

    public List<Role> getRecords() {
        return Records;
    }

    public void setRecords(List<Role> Records) {
        this.Records = Records;
    }   
}

從spring方法getAllRoles（）返回的JSON是

{"result":"OK","records":[
{"custId":"1","name":"aaa","birthYear":"1982","employer":"XX","infoAsOfDate":"20130110","disabled":"true"},
{"custId":"2","name":"bbb","birthYear":"1982","employer":"YY","infoAsOfDate":"20130111","disabled":"true"},
{"custId":"3","name":"ccc","birthYear":"1982","employer":"XX","infoAsOfDate":"20130108","disabled":"false"},
{"custId":"4","name":"ddd","birthYear":"1981","employer":"TT","infoAsOfDate":"20130107","disabled":"true"}
]}

我需要JSON作為-[兩個元素中都注意大寫R]

{"Result":"OK","Records":[ ....................
 ..............................................
]}

使用Jakson映射器創建JSON響應時要考慮到對象的getter / setter名稱。如何獲得所需的JSON響應格式？

Answer 1

您可以使用注釋@JsonProperty自定義名稱：

@JsonProperty("Result")
public String getResult() {
    return Result;
}

如果您需要所有屬性名稱都將首字母大寫，則可以通過擴展PropertyNamingStrategy來更改默認命名約定。 例如，您可以閱讀此博客文章http://www.cowtowncoder.com/blog/archives/2011/03/entry_448.html 。