Python找出最大數量？

Question

編寫一個程序，反復提示用戶輸入整數，直到用戶輸入“完成”。 輸入“完成”后，打印出最大和最小的數字。 如果用戶輸入的不是有效數字的任何內容，則使用 try/except 捕獲它並發出適當的消息並忽略該數字。

到目前為止我有這個，但我對如何創建一種比較最大值的方法感到困惑？ 我是編程新手，我只是在尋求幫助。 我還包括 try 和 except 塊之前的 while 與 try 嗎？ 然后錯誤除外？

 largest = None
 smallest = None
 while True:
     num = raw_input("Enter a number: ")
     if num == "done" : break
       print num

 print "Maximum", largest

Answer 1

nums = []
while True:
  n = raw_input("Enter a number: ")
  if n == "done":
    break
  try:
    nums.append(int(n))
  except ValueError:
    print "Invalid input"

print "Min: %d" % min(nums)
print "Max: %d" % max(nums)

Answer 2

largest = None
smallest = None
first_number = True

while True:
    num = raw_input("Enter a number: ")
    if num == "done" : break

    try:
        num = int(num)
        if first_number:
            largest = num
            smallest = num
            first_number = False
        else:
            largest = max(largest, num)
            smallest = min(smallest, num)
    except Exception, e:
        print "Not Valid Input!!!"
        continue

print "Maximum", largest
print "Minimum", smallest

Answer 3

numbers =[]
while True:
     num = raw_input("Enter a number: ")
     if num == "done" :
         break
     else:
         numbers.append(num)

print max(numbers)
print min(numbers)

因此，邏輯是將數字添加到列表中並使用函數 max 和 min。 您可以編寫代碼來自己處理異常。

Answer 4

largest =  None
smallest = None

while True:
   num = raw_input("Enter a number: ")
   if num == "done": break
   if len(num) < 1 : break
   try:
    num=int(num)
   except:
    print "Invalid input"
    continue
    if num is smallest:
      smallest = num
    if num > largest:
      largest = num
print "Maximum is ", largest
print "Minimum is ", smallest

Answer 5

您可以通過對原始程序進行非常小的修改來做到這一點：只需在您考慮的時候保留最小和最大數字的標簽。

largest  = None
smallest = None

while True:
    string = raw_input("Enter a number: ")

    if string == "done":
        break

    try:
        num = int(string)
    except ValueError:
        print "Not a number"
        continue

    if largest is None or num > largest:
        largest = num

    if smallest is None or num < smallest:
        smallest = num

Answer 6

largest = None
smallest = None

while True:
num = raw_input('Enter a number: ')

if num == 'done':
    print 'Maximum is %s' % largest
    print 'Minimum is %s' % smallest
    break

try:
    num = int(num)

    if smallest is None or num <= smallest:
        smallest = num

    if largest is None or num >= largest:
        largest = num

except:
    print 'Invalid input'

Answer 7

我也是一名 Python 初學者，我在 Charles Russell Severance 的“Python for Everyone” 中注意到了這個問題。 我的回答如下。

prompt = 'Enter the number: '
initial_value = 0.0
while True:
    thing = input(prompt)
    if thing == 'done':
        break
    try:
        num = float(thing)
    except:
        print('Invalid input')
        continue
    num = float(thing)
    if num > initial_value:
        max = num
        min = initial_value
    else:
        min = num
print('Max', max)
print('Min', min)

Answer 8

通過將num分配給單個值，您將在循環的每次迭代中覆蓋它。 改用列表。

num = []
finish = "n"
while finish.lower() == "n"
    try:
        num.append(int(raw_input("Enter a number: ")))
    except ValueError:
         print "Not a number"
    finish = raw_input("Would you like to add another number? (y/n): ")

print max(num)