Java Regex - 拆分逗号分隔列表，但在括号内排除逗号

Question

I'm trying to write regex that will split a Java string like this:

300x250,468x60,300x400v(480x320,768x1024,100x100),400x300v,640x480v(200x200,728x90)

in to something like this:

300x250 
468x60
300x400v(480x320,768x1024,100x100)
400x300v
640x480v(200x200,728x90)

I've been trying \,(\()? but this ends up selecting the commas in the parentheses as well.

Answer 1

If you have to use regex you can split on ,(?![^(]*\\))

If not then one simple iteration over characters can do the trick

String data="300x250,468x60,300x400v(480x320,768x1024,100x100),400x300v,640x480v(200x200,728x90)";

List<String> tokens=new ArrayList<>();
StringBuilder buffer=new StringBuilder();

int parenthesesCounter=0;

for (char c : data.toCharArray()){
    if (c=='(') parenthesesCounter++;
    if (c==')') parenthesesCounter--;
    if (c==',' && parenthesesCounter==0){
        //lets add token inside buffer to our tokens
        tokens.add(buffer.toString());
        //now we need to clear buffer  
        buffer.delete(0, buffer.length());
    }
    else 
        buffer.append(c);
}
//lets not forget about part after last comma
tokens.add(buffer.toString());

String[] splitedArray=tokens.toArray(new String[tokens.size()]);

//lets test what is inside our array
for (String s : splitedArray)
    System.out.println(s);

Output

300x250
468x60
300x400v(480x320,768x1024,100x100)
400x300v
640x480v(200x200,728x90)

Answer 2

akburg, resurrecting this question for completion because it had another simple solution that wasn't mentioned. This situation is similar to Match (or replace) a pattern except in situations s1, s2, s3 etc .

Here's our simple regex:

\([^)]*\)|(,)

The left side of the alternation matches complete (parentheses) tags. We will ignore these matches. The right side matches and captures commas to Group 1, and we know they are the right commas because they were not matched by the expression on the left.

This program shows how to use the regex (see the results at the bottom of the online demo ):

import java.util.*;
import java.io.*;
import java.util.regex.*;
import java.util.List;

class Program {
public static void main (String[] args) throws java.lang.Exception  {

String subject = "300x250,468x60,300x400v(480x320,768x1024,100x100),400x300v,640x480v(200x200,728x90)";
Pattern regex = Pattern.compile("\\([^)]*\\)|(,)");
Matcher m = regex.matcher(subject);
StringBuffer b= new StringBuffer();
while (m.find()) {
if(m.group(1) != null) m.appendReplacement(b, "SplitHere");
else m.appendReplacement(b, m.group(0));
}
m.appendTail(b);
String replaced = b.toString();
String[] splits = replaced.split("SplitHere");
for (String split : splits) System.out.println(split);
} // end main
} // end Program

Reference

How to match (or replace) a pattern except in situations s1, s2, s3...