使用atoi填充一组int

Question

First time asking a question on here. Apologies if there's already threads about this but i had a few searches and didn't quite find what i think i was looking for. I'm very new to C and am working through a few homework exercises for my microcontroller systems class. We're currently working through easy exercises before we get into embedded C and I'm trying to write a program that'll take a line of text consisting of 10 numbers separated by commas and fill an array of int s with it. As a hint we were told to use a substring and atoi . I think i'm close to getting it right but i can't get it to output my numbers properly.

Also i'm not looking spoon fed answers. A few hints would suffice for now. I'd like to try figuring it out myself before asking for the solution.

Here is my code:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    int a[10];
    char str[] = {1,2,3,4,5,6,7,8,9,10}; //contains string of numbers
    int i;
    puts("This prints out ten numbers:");

    for (i = 0; i < 10; i++)
    {
        a[i] = atoi(str);
        printf("%d", a[i]);
            //i'm guessing the problem lies in one of the above two lines
    }
    return 0;
}

This is outputting the following:

This prints out ten numbers:
0000000000

Thanks to anyone that can help! Chris

Answer 1

You said that you have to use a line of text separated by commas but you've actually declared a char array containing ten (binary) integers. To get that into a string you just need to do this:

char str[] = "1,2,3,4,5,6,7,8,9,10";

Then you'll need someway to process this string to get each number out and into your array of int .

Answer 2

First off, you should declare a string as follows:

char str[] = {"1,2,3,4,5,6,7,8,9,10"};

the " made the numbers a whole string. Next, you'll need to tokenize them and using the <string.h> library which will come quite handy in this situation.

Here is how you do tokenizing:

define a token buffer first:

char* token;

token = strtok(str,",");   //think of it as substring, the part of the str before the comma
for (i = 0; i < 10; i++)
{
    a[i] = atoi(token);
    printf("%d\t", a[i]);
            //i'm guessing the problem lies in one of the above two lines
    token = strtok(NULL, ","); //this line is also required for tokenizing the next element
}

Using the strtok() function, you separated the elements between the comas, and got yourself the number strings. Used atoi() function to convert them into integers and printed them. You can see this reference for strtok() function for better understanding.

Answer 3

The problem lies in how you're creating the string.
Please excuse my previous answer, I misunderstood your question:

Simply put, the declaration should be as follows:

char str[] = "1,2,3,4,5,6,7,8,9, 10, 12";

Next, you can use strtok to separate the string into an array of strings omittied the separator (which is in your case the comma), then pass the array members to atoi

Now, why is your code not working?
First, characters should be surrounded by the apostrophes or else the compiler will take the number you pass literally as the ASCII value.

Second, arrays in C like this: char str[] = {'1', '2', '3', '4', '5'}; don't mean a comma separated string, these commas separate the ARRAY members, each in its own index and not as a whole string.

Answer 4

Your definition of char str[] = {1,2,3,4,5,6,7,8,9,10}; actually sets the values of the chars to 1 to 10.

In the ASCII-chart of characters, these are unprintable control-characters. Writing '1' instead of 1 will set the value to the ASCII-value of 1, which is 0x31.

another mistake is that the commas in your definition only seperate the values in the definition, so the result is a array of chars without any seperation, so 12345678910.

so the correct way would be char str[] = "1,2,3,4,5,6,7,8,9,10";