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Javascript-我无法在字符串的开头连接

[英]Javascript - I can't concatenate at the beginning of my string

Here's what I want to do: 这是我想做的:

Check if there is the first character "@" within my string, If not, add it. 检查我的字符串中是否有第一个字符“ @”,如果没有,请添加它。

Here is my code: 这是我的代码:

$(document).ready(function(){

    $("#twitter").blur(function() {
            var s = $("#twitter").val();
            alert(s);
            var isAt = s.charAt(0);
            alert(isAt);
            if(isAt !== "@") {
                alert("lol");
                s = "@" + s;
            }
        });
});

The Problem: 问题:

When I tab to the next input (in turn blurring #twitter) Its lol'ing but not setting the value of the input to "@Rick" when I type "Rick". 当我切换到下一个输入时(依次模糊#twitter),当我键入“ Rick”时,它会哈哈但没有将输入的值设置为“ @Rick”。

Any ideas why? 有什么想法吗?

Change this: 更改此:

s = "@" + s;

to this: 对此:

$("#twitter").val('@' + s);

The problem is that you're updating the value stored in your s reference, but there's no dynamic binding between that variable and the input field itself (ie, you have to still update the #twitter value manually). 问题在于您正在更新存储在s引用中的值,但是该变量与输入字段本身之间没有动态绑定(即,您仍然#twitter手动更新#twitter值)。


Edit: as suggested by @epascarello below, this is probably a cleaner solution: 编辑:如下@epascarello所建议,这可能是一种更清洁的解决方案:

$(document).ready(function(){
    $('#twitter').blur(function() {
        var $this = $(this),
            val = $this.val();
        if (val.charAt(0) !== '@') {
            $this.val('@' + val);
        }
    });
});

And... just for the heck of it, another approach: 还有...只是为了它,另一种方法是:

$(document).ready(function(){
    $('#twitter').blur(function() {
        if (this.value.charAt(0) === '@') return;
        $(this).val(function(i, v) { return '@' + v });
    });
});

One more... 多一个...

$(document).on('blur', '#twitter', function() {
    $(this).val(function(i, v) {
        return v.replace(/(@)?(.*)/, '@$2')
    });
});

Note: you should probably use the first or second one... i'm getting esoteric over here... 注意:您可能应该使用第一个或第二个...我在这里变得很深奥...

$(document).ready(function(){
    $("#twitter").blur(function() {
        var s = $("#twitter").val();
        alert(s);
        var isAt = s.charAt(0);
        alert(isAt);
        if(isAt !== "@") {
            alert("lol");
            $("#twitter").val("@" + s);
        }
    });
});

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