具有透明纹理，然后具有不透明颜色的绘图

Question

I initialize OpenGL like so to make transparent textures transparent:

glEnable(GL_BLEND);
glBlendFunc(GL_SRC_ALPHA, GL_ONE_MINUS_SRC_ALPHA);

I draw my texture like this:

glPushMatrix();
    //translate
    //neutralize colors
    //bind texture
    //vertex points
glPopMatrix();

But when I try to draw a quad immediately afterwards, it won't show up:

glPushMatrix();
{
    glTranslatef(x, y, 0);
    glColor3f(1f, 0f, 0f);
    glBegin(GL_QUADS);
    {           
        glVertex2f(0, 0);
        glVertex2f(10, 0);
        glVertex2f(10, 10);
        glVertex2f(0, 10);
    }
    glEnd();
}
glPopMatrix();

If I remove the initialization above, the quad appears, but then my texture is no longer transparent.

What am I doing wrong here?

Edit: Should I call glDisable(GL_BLEND); whenever I want to draw something that is not a texture?

Answer 1

You need to disable blending before drawing your quad.

EDIT: Can you post more code? The problem may be somewhere else, for example if you have not disabled the texture before drawing the quads.

Answer 2

There's no need to disable blending when drawing.

I call glBlendFunc(GL_SRC_ALPHA, GL_ONE) when I need to draw transparent cubes (with texture).

I usually disable DEPTH test upon drawing with blend mode enabled:

    glEnable(GL_BLEND);                // Turn Blending On
    glDisable(GL_DEPTH_TEST);          // Turn Depth Testing Off

NeHe has a nice tutorial on blending .