简体   繁体   English

C:访问函数中struct的成员

[英]C: accessing members of struct in a function

I'm trying to use the struct member 'size' in my function print_shoe, but my for loop doesn't run. 我试图在我的函数print_shoe中使用结构成员'size',但我的for循环不运行。 However, if I replace 'c->size' with an int in the for loop, it runs just fine 但是,如果我用for循环中的int替换'c-> size',它运行就好了

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define DECK_SIZE 52
#define NUM_FACES 13
#define NUM_SUITS 4
#define LENGTH_FACES 6
#define LENGTH_SUITS 9

typedef struct cards {
  char suits[NUM_SUITS][LENGTH_SUITS];
  char faces[NUM_FACES][NUM_FACES];
  int suit, face, card, value, size;
  int *values[NUM_FACES];
} cards;

char buf[101];
void print_shoe();
void init_decks();
int rand_int();
void shuffle();

int main(void) {

  srand( time(NULL) );

  int decks_input = 0;    
  int numberOfDecks = 1;

  do {
    printf("\nEnter number of decks to be used in the game (1-8):\n\n");
    if (fgets(buf, sizeof(buf), stdin) != NULL)
      if (sscanf (buf, "%d", &decks_input))
        numberOfDecks = decks_input;
     } while (numberOfDecks < 1 || numberOfDecks > 8);

  cards *shoe = malloc(sizeof(cards) * numberOfDecks * DECK_SIZE);
  shoe->size = numberOfDecks * DECK_SIZE;

  shuffle(shoe);
  print_shoe(shoe);

  free(shoe);

  return 0;
}

void print_shoe(cards *c) {
  int i;
  for (i = 0; i < c->size; i++) {
    printf("card #%d = %s of %s\n", i+1, c->faces[c[i].face], c->suits[c[i].suit]);
  }
}

void init_decks(cards *c) {
  int i;
  for (i = 0; i < c->size; i++) {
    c[i].card = i;
    c[i].suit = c[i].card % NUM_SUITS;
    c[i].face = c[i].card % NUM_FACES;
  }  
}

void shuffle(cards *c) {
  init_decks(c);

  int i, j;
  cards tmp;
  for (i = c->size - 1; i > 0 ; i--) {
    j = rand_int(i + 1);
    tmp = c[j];
    c[j] = c[i];
    c[i] = tmp;
  }
}

int rand_int(int n) {
  int limit = RAND_MAX - RAND_MAX % n;
  int rnd;

  do {
    rnd = rand();
     } while (rnd >= limit);
  return rnd % n;
}

Edit: Question has been updated extensively in response to comments that it needed more clarification 编辑:问题已经广泛更新,以回应需要进一步澄清的评论

In the revised code, you have: 在修订后的代码中,您有:

cards *shoe = malloc(sizeof(cards) * numberOfDecks * DECK_SIZE);
shoe->size = numberOfDecks * DECK_SIZE;

// You probably need init_decks(shoe); here!!!

shuffle(shoe);
print_shoe(shoe);

Your code in print_shoe() is simply printing, but you've not initialized the data from malloc() other than the size, so you're printing garbage. print_shoe()代码只是打印,但是你没有初始化malloc()以外的数据,所以你要打印垃圾。 The data returned by malloc() is uninitialized and must be initialized before it is read. malloc()返回的数据未初始化,必须在读取之前进行初始化。 The question changed while I was typing; 我打字的时候问题发生了变化; you still haven't called init_decks(shoe); 你还没有打电话给init_decks(shoe); as you need to. 如你所愿。


This is not why it isn't working — I'm not sure what the problem is now — but it is almost worth commenting on. 这不是它不起作用的原因 - 我不确定现在的问题是什么 - 但它几乎值得评论。 You have: 你有:

void shuffle(cards *c) {
  init_decks(c);

  int i, j;
  cards tmp;
  for (i = c->size - 1; i > 0 ; i--) {
    j = rand_int(i + 1);
    tmp = c[j];
    c[j] = c[i];
    c[i] = tmp;
  }
}

If you're going to use the C99 technique of declaring variables with minimal scope, then you should be writing: 如果您打算使用C99技术来声明具有最小范围的变量,那么您应该写:

void shuffle(cards *c) {
  init_decks(c);
  for (int i = c->size - 1; i > 0; i--) {
    int j = rand_int(i + 1);
    cards tmp = c[j];
    c[j] = c[i];
    c[i] = tmp;
  }
}

(I wouldn't have missed the call to init_decks() had it been written like that.) (我不会错过对init_decks()的调用, init_decks()它是这样编写的。)


As noted in a comment, your cards structure is rather top-heavy. 正如评论中所指出的,您的cards结构相当重要。 You allocate (for each card) enough space to store the ranks and suits that it could possibly have. 您为每张卡分配足够的空间来存储它可能具有的等级和套装。 This is really not necessary. 这实际上没有必要。

This code separates a Deck from a Card . 此代码将DeckCard分开。 It uses a flexible array member in the Deck structure to hold the cards, which is convenient. 它在Deck结构中使用一个灵活的阵列成员来固定卡片,这很方便。 You may prefer to use a regular pointer there, in which case you'll need a pair of memory allocations and a function deck_free() to release the memory allocated by deck_alloc() . 您可能更喜欢在那里使用常规指针,在这种情况下,您需要一对内存分配和一个函数deck_free()来释放由deck_alloc()分配的内存。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

#define NUM_FACES 13
#define NUM_SUITS 4
#define DECK_SIZE (NUM_FACES * NUM_SUITS)
#define LENGTH_FACES 6
#define LENGTH_SUITS 9

static const char suits[NUM_SUITS][LENGTH_SUITS] =
{
    "Clubs",
    "Diamonds",
    "Hearts",
    "Spades"
};
static const char faces[NUM_FACES][NUM_FACES] =
{
    "Ace",
    "Deuce",
    "Three",
    "Four",
    "Five",
    "Six",
    "Seven",
    "Eight",
    "Nine",
    "Ten",
    "Jack",
    "Queen",
    "King",
};

typedef struct Card
{
  int suit;
  int face;
  int card;
} Card;

typedef struct Deck
{
  int size;
  Card cards[];     // Flexible array member
} Deck;

void print_shoe(const Deck *d);
void init_decks(Deck *d);
int rand_int(int n);
void shuffle(Deck *d);
static Deck *deck_alloc(int numberOfDecks);

int main(void)
{
    srand( time(NULL) );
    int numberOfDecks = 1;

    do
    {
        char buf[101];
        printf("\nEnter number of decks to be used in the game (1-8):\n\n");
        if (fgets(buf, sizeof(buf), stdin) != NULL)
        {
            int decks_input;    
            if (sscanf (buf, "%d", &decks_input))
                numberOfDecks = decks_input;
        }
    } while (numberOfDecks < 1 || numberOfDecks > 8);

    Deck *shoe = deck_alloc(numberOfDecks);
    shuffle(shoe);
    print_shoe(shoe);
    free(shoe);

    return 0;
}

static Deck *deck_alloc(int numberOfDecks)
{
    Deck *shoe  = malloc(sizeof(Deck) + (sizeof(Card) * numberOfDecks * DECK_SIZE));
    if (shoe == 0)
    {
        fprintf(stderr, "out of memory\n");
        exit(1);
    }
    shoe->size = numberOfDecks * DECK_SIZE;
    return shoe;
}

void print_shoe(const Deck *d)
{
    for (int i = 0; i < d->size; i++)
        printf("card #%d = %s of %s\n", i+1, faces[d->cards[i].face], suits[d->cards[i].suit]);
}

void init_decks(Deck *d)
{
    for (int i = 0; i < d->size; i++)
    {
        d->cards[i].card = i;
        d->cards[i].suit = d->cards[i].card % NUM_SUITS;
        d->cards[i].face = d->cards[i].card % NUM_FACES;
    }  
}

void shuffle(Deck *d)
{
    init_decks(d);
    for (int i = d->size - 1; i > 0 ; i--)
    {
        int j = rand_int(i + 1);
        Card tmp = d->cards[j];
        d->cards[j] = d->cards[i];
        d->cards[i] = tmp;
    }
}

int rand_int(int n)
{
    int limit = RAND_MAX - RAND_MAX % n;
    int rnd;

    do
    {
        rnd = rand();
    } while (rnd >= limit);
    return rnd % n;
}

Sample output: 样本输出:

$ ./cards

Enter number of decks to be used in the game (1-8):

1
card #1 = Eight of Clubs
card #2 = Jack of Clubs
card #3 = Deuce of Diamonds
card #4 = Jack of Hearts
card #5 = Queen of Clubs
card #6 = Four of Hearts
card #7 = Six of Spades
card #8 = King of Hearts
card #9 = Five of Spades
card #10 = King of Clubs
card #11 = Deuce of Clubs
card #12 = King of Spades
card #13 = Four of Spades
card #14 = Nine of Diamonds
card #15 = Five of Hearts
card #16 = Deuce of Spades
card #17 = Ten of Clubs
card #18 = Five of Diamonds
card #19 = Ten of Spades
card #20 = Three of Spades
card #21 = Nine of Hearts
card #22 = Six of Clubs
card #23 = Ace of Clubs
card #24 = Three of Clubs
card #25 = Queen of Hearts
card #26 = Jack of Diamonds
card #27 = Nine of Clubs
card #28 = Four of Clubs
card #29 = Seven of Spades
card #30 = Ace of Diamonds
card #31 = Six of Diamonds
card #32 = Three of Hearts
card #33 = Queen of Diamonds
card #34 = Ten of Hearts
card #35 = Ten of Diamonds
card #36 = Seven of Diamonds
card #37 = Seven of Clubs
card #38 = Deuce of Hearts
card #39 = Ace of Hearts
card #40 = Jack of Spades
card #41 = Eight of Diamonds
card #42 = Eight of Spades
card #43 = Ace of Spades
card #44 = Three of Diamonds
card #45 = Queen of Spades
card #46 = Five of Clubs
card #47 = Four of Diamonds
card #48 = King of Diamonds
card #49 = Nine of Spades
card #50 = Eight of Hearts
card #51 = Six of Hearts
card #52 = Seven of Hearts
$

Addressing the question directly and ignoring the wisdom of this approach, your problem is as follows(as also mentioned by Raymond Chen). 直接解决这个问题并忽略了这种方法的智慧,你的问题如下(Raymond Chen也提到过)。

  cards *shoe = malloc(sizeof(cards) * numberOfDecks * DECK_SIZE);

The line above makes shoe point to enough memory to store (numberOfDecks * DECK_SIZE) struct cards . 上面的一(numberOfDecks * DECK_SIZE)鞋子指向足够的内存来存储(numberOfDecks * DECK_SIZE) struct cards The structs, and thus there members, are all unitialized at this point meaning shoe[i].size could be any sequence of bits. 结构,因而有成员,在这一点上都是单元化的,这意味着shoe[i].size可以是任何比特序列。

shoe->size = numberOfDecks * DECK_SIZE; shoe-> size = numberOfDecks * DECK_SIZE;

This line looks at the only the first struct cards and sets its size to (numberOfDecks * DECK_SIZE) . 此行查看第一个 struct cards并将其size设置为(numberOfDecks * DECK_SIZE) The rest of the struct cards 's size members remain unititialized. 其余struct cardssize成员仍然是单元化的。

In shuffle , your call to init_decks initializes card , suit , and face but not size . shuffle ,您对init_decks的调用初始化cardsuitface但不是size When you later shuffle the cards, a card with an unititialized size member has a good chance of becoming first. 当您稍后洗牌时,具有单元size成员的卡很有可能成为第一名。

Thus, under your current approach, the following should get what you want if you add this line to init_decks . 因此,根据您当前的方法,如果将此行添加到init_decks ,以下内容应该会得到您想要的init_decks

void init_decks(cards *c) {
      int i;
      int size = c->size;
      for (i = 0; i < c->size; i++) {
            c[i].size = size;
            c[i].card = i;
            c[i].suit = c[i].card % NUM_SUITS;
            c[i].face = c[i].card % NUM_FACES;
       }  
}

You have declared a pointer but haven't initialized it a valid memory location to point to. 您已声明指针但尚未将其初始化为指向的有效内存位置。

 ex *ex_p = malloc(sizeof(ex));
 ex_p->size = 10;

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM