正则表达式查找第二个和第三个斜杠之间的文本

Question

I would like to capture the text that occurs after the second slash and before the third slash in a string. Example:

/ipaddress/databasename/

I need to capture only the database name. The database name might have letters, numbers, and underscores. Thanks.

Answer 1

How you access it depends on your language, but you'll basically just want a capture group for whatever falls between your second and third "/". Assuming your string is always in the same form as your example, this will be:

/.*/(.*)/

If multiple slashes can exist, but a slash can never exist in the database name, you'd want:

/.*/(.*?)/

Answer 2

/.*?/(.*?)/

Answer 3

The regex would be:

/[^/]*/([^/]*)/

so in Perl, the regex capture statement would be something like:

($database) = $text =~ m!/[^/]*/([^/]*)/!;

Normally the / character is used to delimit regexes but since they're used as part of the match, another character can be used. Alternatively, the / character can be escaped:

($database) = $text =~ /\/[^\/]*\/([^\/]*)\//;

Answer 4

You can even more shorten the pattern by going this way:

[^/]+/(\w+)

Answer 5

you can use explode function with PHP or split with other languages to so such operation.

anyways, here is regex pattern:

/[\/]*[^\/]+[\/]([^\/]+)/

Answer 6

I know you specifically asked for regex, but you don't really need regex for this. You simply need to split the string by delimiters (in this case a backslash), then choose the part you need (in this case, the 3rd field - the first field is empty).