正则表达式在最后两个斜杠之间获取文本

Question

Taking a string with the following three examples...

/Services/Research/Consumer-services/Mobile-Services/
/Services/Research/Consumer-services/Fixed-Broadband-and-Multi-Play/
/Services/Research/Consumer-services/Next-Generation-Services/

I need to:

a) Strip so I only have the string contained between the two final slashes (ie. "Mobile-Services") ... /.*/(.*)/ seems to accomplish this, though I don't fully understand ti.

b) Replace dashes in the remaining text with spaces. So, "Mobile-Services" becomes "Mobile Services" and "Fixed-Broadband-and-Multi-Play" becomes "Fixed Broadband and Multi Play"

Thank-you very much.

Answer 1

You can use this regex to capture last part:

/([^/]+)/?$

And use captured group #1

RegEx Demo

Answer 2

You can use following regex for get the last string :

/(\w+-\w+)/$

The anchor $ will matches right after the last character in the string.

Demo